c++中過載運算子來實現2*3矩陣相加
阿新 • • 發佈:2019-02-04
矩陣相加
#include <iostream> using namespace std; class aaa { private: int a[2][3]; public: friend aaa operator+(aaa&A,aaa&B); friend ostream& operator<<(ostream&,aaa&); friend istream& operator>>(istream&,aaa&); aaa(){}; }; aaa operator+(aaa&A,aaa&B) { aaa c; for(int i=0;i<2;i++) for(int j=0;j<3;j++) c.a[i][j]=A.a[i][j]+B.a[i][j]; return c; } istream & operator >> (istream &input,aaa &a) { cout<<"請輸入矩陣: "<<endl; for(int i=0;i<2;i++) for(int j=0;j<3;j++) input>>a.a[i][j]; return input; } ostream & operator << (ostream &output,aaa &C) { cout<<"矩陣相加的結果為:"<<endl; for(int i=0;i<2;i++) { for(int j=0;j<3;j++) output<<C.a[i][j]<<" "; cout<<endl; } return output; } int main() { aaa A,B,C; cin>>A; cin>>B; C=A+B; cout<<C; return 0; }