Java中計算兩個時間差(精確到毫秒)
阿新 • • 發佈：2019-02-07
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
long between = 0;
try {
java.util.Date begin = dfs.parse("2009-07-10 10:22:21.214");
java.util.Date end = dfs.parse("2009-07-20 11:24:49.145");
between = (end.getTime() - begin.getTime());// 得到兩者的毫秒數
} catch (Exception ex) {
ex.printStackTrace();
}
long day = between / (24 * 60 * 60 * 1000);
long hour = (between / (60 * 60 * 1000) - day * 24);
long min = ((between / (60 * 1000)) - day * 24 * 60 - hour * 60);
long s = (between / 1000 - day * 24 * 60 * 60 - hour * 60 * 60 - min * 60);
long ms = (between - day * 24 * 60 * 60 * 1000 - hour * 60 * 60 * 1000
- min * 60 * 1000 - s * 1000);
System.out.println(day + "天" + hour + "小時" + min + "分" + s + "秒" + ms
+ "毫秒");
long between = 0;
try {
java.util.Date begin = dfs.parse("2009-07-10 10:22:21.214");
java.util.Date end = dfs.parse("2009-07-20 11:24:49.145");
between = (end.getTime() - begin.getTime());// 得到兩者的毫秒數
} catch (Exception ex) {
ex.printStackTrace();
}
long day = between / (24 * 60 * 60 * 1000);
long hour = (between / (60 * 60 * 1000) - day * 24);
long min = ((between / (60 * 1000)) - day * 24 * 60 - hour * 60);
long s = (between / 1000 - day * 24 * 60 * 60 - hour * 60 * 60 - min * 60);
long ms = (between - day * 24 * 60 * 60 * 1000 - hour * 60 * 60 * 1000
- min * 60 * 1000 - s * 1000);
System.out.println(day + "天" + hour + "小時" + min + "分" + s + "秒" + ms
+ "毫秒");