有食物與飲料兩個限制條件 之前還在想怎麼連邊

後來想到可以s與食物連邊 流量為食物數量 飲料與t連 流量為飲料數量 這樣問題就完美解決了 然後食物與人連 人與飲料連 流量為1 其中人要拆點 來控制人的數量 兩個點之間連流量為1

寫錯了個小細節之前

#include<cstdio>
#include<string>
#include<map>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long LL;
const int maxn = 1e3 + 10;
map<string, int> M;
char s[maxn * 100];
string x, y;
int n, t, z, f;

struct point
{
    int l[31], r[31], flag;
    void read()
    {
        flag = 1;
        for (int i = 1; i <= 30; i++) l[i] = -10001, r[i] = 10001;
        gets(s);
        for (int i = 0; s[i]; )
        {
            if (s[i] == ' ' || s[i] == ',') { i++; continue; }
            x = "";    y = "";    z = 0;    f = 1;
            while (s[i] != ' ') x += s[i++];
            while (s[i] == ' ') ++i;
            while (s[i] != ' ') y += s[i++];
            while (s[i] == ' ') ++i;
            if (s[i] == '-') ++i, f = -1;
            while (s[i] >= '0'&&s[i] <= '9') z = z * 10 + s[i++] - '0';
            z = z*f;
            int now = M[x];
            if (!now) now = M[x] = ++t;
            if (y == "<") r[now] = min(r[now], z - 1);
            else if (y == ">") l[now] = max(l[now], z + 1);
            else if (y == "<=") r[now] = min(r[now], z);
            else if (y == ">=") l[now] = max(l[now], z);
            else l[now] = max(l[now], z), r[now] = min(r[now], z);
            if (l[now] > r[now]) flag = 0;
        }
    }
}a[maxn];

bool check(point a, point b)
{
    if (a.flag + b.flag != 2) return false;
    for (int i = 1; i <= t; i++)
    {
        if (max(a.l[i], b.l[i]) > min(a.r[i], b.r[i])) return false;
    }
    return true;
}

int main()
{
    while (scanf("%d", &n) != EOF)
    {
        gets(s);
        M.clear();    t = 0;
        for (int i = 1; i <= n; i++) a[i].read();
        for (int i = 1; i <= n; i++)
        {
            int flag = 0;
            for (int j = 1; j < i; j++)
            {
                if (check(a[i], a[j]))
                {
                    if (flag) printf(" ");
                    printf("%d", j);
                    flag = 1;
                }
            }
            if (!flag) printf("unique");
            printf("\n");
        }
    }
    return 0;
}