leetcode 1:two sum(C語言)
int i=0,j=0;
int*res = NULL;
res = malloc(2*sizeof(int));
res[0]= res[1]= 0;
for(i=0;i<numsSize;i++){
for(j=i+1;j<numsSize;j++){
if(nums[i]+nums[j]==target){
res[0]=i;
res[1]=j;
return res;
}
}
}
return res;
}
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