以下是以C語言解決該問題的程式碼：

#include<stdio.h>
int main()
{
    int i,n=0;
    float real[20],average,sum;
    printf("Please enter 20 real numbers:\n");
    for(i=0;i<20;i++)   //迴圈20次接收資料
        scanf("%f",&real[i]);
    for(i=0;i<20;i++)   //對20個實數求和
        sum+=real[i];
    average=sum/20.0;   //求平均值
    for
 
(i=0;i<20;i++)   //求高於平均的數的個數
    {
        if(real[i]>average)
            n++;
    }
    printf("The average value is %f.\n",average);   //輸出平均值
    printf("The number of more than average value is %d.\n",n); //輸出高於平均的數的個數
    return 0;
}

輸出結果如下：

Please enter 20 real numbers:
1
2
3
4
5
6
7
8
9
10
11
 

12
13
14
15
16
17
18
19
20
The average value is 10.500000.
The number of more than average value is 10.