程式碼:

# coding=utf-8

'''
作者:Jairus Chan
程式:多項式曲線擬合演算法
'''
import matplotlib.pyplot as plt
import math
import numpy
import random

fig = plt.figure()
ax = fig.add_subplot(111)

#階數為9階
order=9

#生成曲線上的各個點
x = numpy.arange(-1,1,0.02)
y = [((a*a-1)*(a*a-1)*(a*a-1)+0.5)*numpy.sin(a*2) for a in x]
#ax.plot(x,y,color='r',linestyle='-',marker='')
#,label="(a*a-1)*(a*a-1)*(a*a-1)+0.5"

#生成的曲線上的各個點偏移一下，並放入到xa,ya中去
i=0
xa=[]
ya=[]
for xx in x:
	yy=y[i]
	d=float(random.randint(60,140))/100
	#ax.plot([xx*d],[yy*d],color='m',linestyle='',marker='.')
	i+=1
	xa.append(xx*d)
	ya.append(yy*d)

'''for i in range(0,5):
	xx=float(random.randint(-100,100))/100
	yy=float(random.randint(-60,60))/100
	xa.append(xx)
	ya.append(yy)'''

ax.plot(xa,ya,color='m',linestyle='',marker='.')


#進行曲線擬合
matA=[]
for i in range(0,order+1):
	matA1=[]
	for j in range(0,order+1):
		tx=0.0
		for k in range(0,len(xa)):
			dx=1.0
			for l in range(0,j+i):
				dx=dx*xa[k]
			tx+=dx
		matA1.append(tx)
	matA.append(matA1)

#print(len(xa))
#print(matA[0][0])
matA=numpy.array(matA)

matB=[]
for i in range(0,order+1):
	ty=0.0
	for k in range(0,len(xa)):
		dy=1.0
		for l in range(0,i):
			dy=dy*xa[k]
		ty+=ya[k]*dy
	matB.append(ty)
 
matB=numpy.array(matB)

matAA=numpy.linalg.solve(matA,matB)

#畫出擬合後的曲線
#print(matAA)
xxa= numpy.arange(-1,1.06,0.01)
yya=[]
for i in range(0,len(xxa)):
	yy=0.0
	for j in range(0,order+1):
		dy=1.0
		for k in range(0,j):
			dy*=xxa[i]
		dy*=matAA[j]
		yy+=dy
	yya.append(yy)
ax.plot(xxa,yya,color='g',linestyle='-',marker='')

ax.legend()
plt.show()
 

執行效果: