python csv模組寫檔案 出現 iterable expected, not int 錯誤
阿新 • • 發佈：2019-02-15
開始程式碼：
import csv
def storFile(data,fileName):
with open(fileName,'w',newline ='') as f:
mywrite = csv.writer(f)
for i in data:
mywrite.writerow(i)
data = [1,0,1,1,0,1,0]
storFile(data,'splitData\wodecesi.csv')報錯：
<ipython-input-33-5de04d85deaa> in storFile(data, fileName) 4 mywrite = csv.writer(f) 5 for i in data: ----> 6 mywrite.writerow(i) 7 data = [1,0,1,1,0,1,0] 8 storFile(data,'splitData\wodecesi.csv') Error: iterable expected, not int
查閱資料發現: csv 的writerow 函式只能寫入一個序列，比如 list 或 array.
修改方法：
（1） 直接讀取整個列表：fsdg
import csv
def storFile(data,fileName):
with open(fileName,'w',newline ='') as f:
mywrite = csv.writer(f)
mywrite.writerow(data)
data = [1,0,1,1,0,1,0]
storFile(data,'splitData\wodecesi.csv')所得csv檔案中，列表元素為 1 0 1 1 0 1 0 排列；
（2）先將每個元素轉換為小列表，再儲存：
import csv
def storFile(data,fileName):
data = list(map(lambda x:[x],data))
with open(fileName,'w',newline ='') as f:
mywrite = csv.writer(f)
for i in data:
mywrite.writerow(i)
data = [1,0,1,1,0,1,0]
storFile(data,'splitData\wodecesi.csv')
data.to_csv('splitData\wodecesi.csv',index = False)
（2）和（3）所得檔案中，元素為縱向排列：
1
0
1
1
0
1
0