統計字串中字母,數字,空格和其他字元的個數。
阿新 • • 發佈:2019-02-16
#include <stdio.h>
int letter,digit,space,others;
int main()
{void count(char []);
char text[80];
printf("input string:\n");
gets(text);
printf("string:");
puts(text);
letter=0;
digit=0;
space=0;
others=0;
count(text);
printf("\nletter:%d\ndigit:%d\nspace:%d\nothers:%d\n",letter,digit,space,others);
return 0;
}
void count(char str[])
{
int i;
for (i=0;str[i]!='\0';i++)
if ((str[i]>='a'&& str[i]<='z')||(str[i]>='A' && str[i]<='Z'))
letter++;
else if (str[i]>='0' && str [i]<='9')
digit++;
else if (str[i]==32)
space++;
else
others++;
}
int letter,digit,space,others;
int main()
{void count(char []);
char text[80];
printf("input string:\n");
gets(text);
printf("string:");
puts(text);
letter=0;
digit=0;
space=0;
others=0;
count(text);
printf("\nletter:%d\ndigit:%d\nspace:%d\nothers:%d\n",letter,digit,space,others);
return 0;
}
void count(char str[])
{
int i;
for (i=0;str[i]!='\0';i++)
if ((str[i]>='a'&& str[i]<='z')||(str[i]>='A' && str[i]<='Z'))
letter++;
else if (str[i]>='0' && str [i]<='9')
digit++;
else if (str[i]==32)
space++;
else
others++;
}