python 實現N個人,從1數到3,數到3的出局,來回循環,最後剩下一個人
阿新 • • 發佈:2019-02-18
循環 == size arraylist pytho add new all code person = []
for i in range(1, 4):
person.append(i)
print ‘person:%s‘ % person
index = 0
while len(person) > 1:
removelist = []
for item in person:
index += 1
if index == 3:
removelist.append(item)
index = 0
print ‘removelist:%s‘ % removelist
for item in removelist:
person.remove(item)
for i in range(1, 4):
person.append(i)
print ‘person:%s‘ % person
index = 0
while len(person) > 1:
removelist = []
for item in person:
index += 1
if index == 3:
removelist.append(item)
index = 0
print ‘removelist:%s‘ % removelist
for item in removelist:
person.remove(item)
print ‘current person list:%s‘ % person print ‘current removelist:%s‘ % removelist
print ‘left person list:%s‘ % person
java 版:
import java.util.ArrayList;
import java.util.List;
public class TestShushu {
public static void main(String[] args) { // TODO Auto-generated method stub List<Integer> list = new ArrayList<Integer>(); for(int i=1;i<4;i++) { list.add(i); } System.out.println(list); int index = 0; while(list.size() > 1) { List<Integer> removelist = new ArrayList<Integer>(); for(int i: list) { index ++; if(index == 3) { removelist.add(i); //System.out.println(removelist); index = 0; } } System.out.println("要刪除的數組" + removelist); list.removeAll(removelist); System.out.println("當前數組元素:" + list); } System.out.println("最後留下的那個編號:" + list); }
}
python 實現N個人,從1數到3,數到3的出局,來回循環,最後剩下一個人