給定一個字符串，你需要反轉字符串中每個單詞的字符順序，同時仍保留空格和單詞的初始順序。

示例 1:

輸入: "Let‘s take LeetCode contest"
輸出: "s‘teL ekat edoCteeL tsetnoc"
註意：在字符串中，每個單詞由單個空格分隔，並且字符串中不會有任何額外的空格。

思路:
    簡單題
    1.強行遍歷逆置
    2.正則,分割字符串,逆置

 1 class Solution557 {
 2 
 3   public String reverseWords(String s) {
 4     char[] arr = s.toCharArray();
 
 5     int end = 0;
 6     int start = 0;
 7     for (end = 0; end < arr.length; end++) {
 8       if (end == arr.length - 1 || arr[end + 1] == ‘ ‘) {
 9         reserve(arr, start, end);
10         start = end + 2;
11       }
12     }
13     return new String(arr);
14   }
15 
16   private void reserve(char
 
[] arr, int start, int end) {
17     int len = end - start + 1;
18     for (int i = 0; i < (len >> 1); i++) {
19       char temp = arr[start + i];
20       arr[start + i] = arr[end - i];
21       arr[end - i] = temp;
22     }
23   }
24 
25 
26   public String reverseWords_2(String s) {
27     StringBuilder res = new
 
 StringBuilder();
28     String[] subs = s.split(" ");
29     for (String sub : subs) {
30       res.append(new StringBuilder(sub).reverse()).append(" ");
31     }
32     res.deleteCharAt(res.length() - 1);
33     return res.toString();
34 
35   }
36 }

LeetCode第557題 反轉字符串中的單詞 III