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hdu 1002 A + B Problem II 高精度加法

tar pre acm add return cli clu target max

題目鏈接http://acm.hdu.edu.cn/showproblem.php?pid=1002

高精度模板題

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#include<iostream>
#include<string>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn = 1010;
int an[maxn], bn[maxn];
string add(string a, string b){
    memset(an, 0, sizeof an);
    memset(bn, 
0, sizeof bn); for (int i = 0; i < a.length(); i++) an[i] = a[a.length() - i - 1] - 0; for (int i = 0; i < b.length(); i++) bn[i] = b[b.length() - i - 1] - 0; int len = max(a.length(), b.length()); for (int i = 0; i < len; i++){ an[i] += bn[i], an[i + 1] += an[i] / 10
, an[i] %= 10; } if (an[len]) len++; string res = ""; for (int i = 0; i < len; i++) res += an[len - 1 - i] + 0; return res; } int main() { int t,k=1; cin >> t; string a, b; while (t--){ cin >> a >> b; cout
<< "Case " << k++ << ":" << endl; cout << a << " + " << b << " = "; cout << add(a, b) << endl; if (t != 0) cout << endl; } return 0; }
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hdu 1002 A + B Problem II 高精度加法