devel 操作 titles group by ble pre nio 員工 nag

CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE IF NOT EXISTS `titles` (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);

輸入描述:

無

輸出描述:

dept_no	dept_name	title	count
d001	Marketing	Senior Engineer	1
d001	Marketing	Staff	1
d002	Finance	Senior Engineer	1
d003	Human Resources	Senior Staff	1
d004	Production	Senior Engineer	2
d005	Development	Senior Staff	1
d006	Quality Management	Engineer	2
d006	Quality Management	Senior Engineer	1

思路：看創建的表以及結果：tiltle是惟一的，需要的是 departments表和title表裏面的dept_no，dept_name和title以及title的重復計數，但是departments和title表沒有直接關系，

1.連接dept_emp和titles表，判斷to_data=‘9999-01-01’ ，d.emp_no=t.emp_no
 
2.連接department和1操作之後的表，條件dept_no==
3.group by dept_no,title

SELECT de.dept_no, dp.dept_name, t.title, COUNT(t.title) AS count
FROM titles AS t INNER JOIN dept_emp AS de 
ON t.emp_no = de.emp_no AND de.to_date = ‘9999-01-01‘ AND t.to_date = ‘9999-01-01‘
INNER JOIN departments AS dp 
ON de.dept_no = dp.dept_no
GROUP BY de.dept_no, t.title

匯總各個部門當前員工的title類型的分配數目，結果給出部門編號dept_no、dept_name、其當前員工所有的title以及該類型title對應的數目count