給定一個較短字串shortStr='ab'，和一個較長字串longStr='adkdabkwelabwkereabrsdweo2342ablk234lksdfsdf1abe'；

判斷shortStr在longStr中出現的次數的方案，要求使用sql實現：

方案一：使用replace函式：

declare @llongStr nvarchar(64)

declare @shortStr nvarchar(16);

set @llongStr='adkdabkwelabwkereabrsdweo2342ablk234lksdfsdf1abe';

set @shortStr='ab';

declare @newStr nvarchar(64);

set @newStr=replace(@llongStr,@shortStr,'');

declare @shortDisplayCount int;

set @shortDisplayCount=(len(@llongStr)-len(@newStr))/len(@shortStr);

select @shortDisplayCount;

列印結果：

方案二：使用charindex和substring實現：

declare @longStr nvarchar(64)

declare @shortStr nvarchar(16);

set @longStr='adkdabkwelabwkereabrsdweo2342ablk234lksdfsdf1abe';

set @shortStr='ab';       

declare @findCount int;

declare @idx int;

set @findCount=0;

while charindex(@shortstr,@longStr)>0

begin

    set @findCount+=1;

    set @idx=charindex(@shortstr,@longStr)

    set @longStr=substring(@longStr,@idx+len(@shortStr),len(@longStr)-@idx);

    print @longStr

end

print @findCount

輸出結果：

kwelabwkereabrsdweo2342ablk234lksdfsdf1abe

wkereabrsdweo2342ablk234lksdfsdf1abe

rsdweo2342ablk234lksdfsdf1abe

lk234lksdfsdf1abe

e

5