SQL HAVING 子句

SQL HAVING 子句


HAVING 子句

在 SQL 中增加 HAVING 子句原因是,WHERE 關鍵字無法與聚合函式一起使用。

HAVING 子句可以讓我們篩選分組後的各組資料。

SQL HAVING 語法

SQL HAVING 語法

SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name HAVING aggregate_function(column_name) operator value;


演示資料庫

在本教程中,我們將使用 itread01 樣本資料庫。

下面是選自 "Websites" 表的資料:

+----+--------------+---------------------------+-------+---------+
| id | name         | url                       | alexa | country |
+----+--------------+---------------------------+-------+---------+
| 1  | Google       | https://www.google.cm/    | 1     | USA     |
| 2  | 淘寶          | https://www.taobao.com/   | 13    | CN      |
| 3  | 入門教學      | http://www.itread01.com/    | 4689  | CN      |
| 4  | 微博          | http://weibo.com/         | 20    | CN      |
| 5  | Facebook     | https://www.facebook.com/ | 3     | USA     |
| 7  | stackoverflow | http://stackoverflow.com/ |   0 | IND     |
+----+---------------+---------------------------+-------+---------+

下面是 "access_log" 網站訪問記錄表的資料:

mysql> SELECT * FROM access_log;
+-----+---------+-------+------------+
| aid | site_id | count | date       |
+-----+---------+-------+------------+
|   1 |       1 |    45 | 2016-05-10 |
|   2 |       3 |   100 | 2016-05-13 |
|   3 |       1 |   230 | 2016-05-14 |
|   4 |       2 |    10 | 2016-05-14 |
|   5 |       5 |   205 | 2016-05-14 |
|   6 |       4 |    13 | 2016-05-15 |
|   7 |       3 |   220 | 2016-05-15 |
|   8 |       5 |   545 | 2016-05-16 |
|   9 |       3 |   201 | 2016-05-17 |
+-----+---------+-------+------------+
9 rows in set (0.00 sec)


SQL HAVING 例項

現在我們想要查詢總訪問量大於 200 的網站。

我們使用下面的 SQL 語句:

例項

SELECT Websites.name, Websites.url, SUM(access_log.count) AS nums FROM (access_log INNER JOIN Websites ON access_log.site_id=Websites.id) GROUP BY Websites.name HAVING SUM(access_log.count) > 200;

執行以上 SQL 輸出結果如下:

現在我們想要查詢總訪問量大於 200 的網站,並且 alexa 排名小於 200。

我們在 SQL 語句中增加一個普通的 WHERE 子句:

例項

SELECT Websites.name, SUM(access_log.count) AS nums FROM Websites INNER JOIN access_log ON Websites.id=access_log.site_id WHERE Websites.alexa < 200 GROUP BY Websites.name HAVING SUM(access_log.count) > 200;

執行以上 SQL 輸出結果如下: