SQL LEFT JOIN 關鍵字
SQL LEFT JOIN 關鍵字
SQL LEFT JOIN 關鍵字
LEFT JOIN 關鍵字從左表(table1)返回所有的行,即使右表(table2)中沒有匹配。如果右表中沒有匹配,則結果為 NULL。
SQL LEFT JOIN 語法
SELECT column_name(s)
FROM table1
LEFT JOIN table2
ON table1.column_name=table2.column_name;
FROM table1
LEFT JOIN table2
ON table1.column_name=table2.column_name;
或:
SELECT column_name(s)
FROM table1
LEFT OUTER JOIN table2
ON table1.column_name=table2.column_name;
FROM table1
LEFT OUTER JOIN table2
ON table1.column_name=table2.column_name;
註釋:在某些資料庫中,LEFT JOIN 稱為 LEFT OUTER JOIN。
演示資料庫
在本教程中,我們將使用 itread01 樣本資料庫。
下面是選自 "Websites" 表的資料:
+----+--------------+---------------------------+-------+---------+ | id | name | url | alexa | country | +----+--------------+---------------------------+-------+---------+ | 1 | Google | https://www.google.cm/ | 1 | USA | | 2 | 淘寶 | https://www.taobao.com/ | 13 | CN | | 3 | 入門教學 | http://www.itread01.com/ | 4689 | CN | | 4 | 微博 | http://weibo.com/ | 20 | CN | | 5 | Facebook | https://www.facebook.com/ | 3 | USA | | 7 | stackoverflow | http://stackoverflow.com/ | 0 | IND | +----+---------------+---------------------------+-------+---------+
下面是 "access_log" 網站訪問記錄表的資料:
mysql> SELECT * FROM access_log; +-----+---------+-------+------------+ | aid | site_id | count | date | +-----+---------+-------+------------+ | 1 | 1 | 45 | 2016-05-10 | | 2 | 3 | 100 | 2016-05-13 | | 3 | 1 | 230 | 2016-05-14 | | 4 | 2 | 10 | 2016-05-14 | | 5 | 5 | 205 | 2016-05-14 | | 6 | 4 | 13 | 2016-05-15 | | 7 | 3 | 220 | 2016-05-15 | | 8 | 5 | 545 | 2016-05-16 | | 9 | 3 | 201 | 2016-05-17 | +-----+---------+-------+------------+ 9 rows in set (0.00 sec)
SQL LEFT JOIN 例項
下面的 SQL 語句將返回所有網站及他們的訪問量(如果有的話)。
以下例項中我們把 Websites 作為左表,access_log 作為右表:
例項
SELECT Websites.name, access_log.count, access_log.date
FROM Websites
LEFT JOIN access_log
ON Websites.id=access_log.site_id
ORDER BY access_log.count DESC;
FROM Websites
LEFT JOIN access_log
ON Websites.id=access_log.site_id
ORDER BY access_log.count DESC;
執行以上 SQL 輸出結果如下:

註釋:LEFT JOIN 關鍵字從左表(Websites)返回所有的行,即使右表(access_log)中沒有匹配。