題目：給你一個二進制串。推斷是否能被131071 整除。

分析：數論。直接模擬除法運算，求出余數就可以。

說明：註意可能有非法字符（比如空格）。

#include <algorithm>
#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>
#include <cmath>

using namespace std;

char buf[10010],temp[110]; 

int main()
{
	int count = 0,len = 0;
	while (~scanf("%s",&temp)) {
		len = strlen(temp);
		count = 0;
		while (temp[len-1] != '#') {
			for (int i = 0 ; i < len ; ++ i)
				if (temp[i] == '0' || temp[i] == '1')
					buf[count ++] = temp[i];
			scanf("%s",&temp);
			len = strlen(temp);
		}
		for (int i = 0 ; i < len ; ++ i)
			if (temp[i] == '0' || temp[i] == '1')
				buf[count ++] = temp[i];
		buf[count] = 0;
		
		int r = 0;
		for (int i = 0 ; i < count ; ++ i) {
			r <<= 1;
			r += buf[i]-'0';
			r %= 131071;
		}
		
		if (r) printf("NO\n");
		else printf("YES\n");
	}
    return 0;
}

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