Python - 字典按值(value)排序
阿新 • • 發佈:2017-06-17
key list odi script dcl nes spl ava port
字典安值排序是一個偽命題.
字典本身是不能被排序的, 已經依照關鍵字(key)排序, 可是列表(list)和元組(tuple)能夠排序, 所以字典須要轉換列表後排序.
如
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))
則是轉換列表後的排序, dict(sorted_x) == x, 列表轉換字典.
代碼
# -*- coding: utf-8 -*-
import operator
x = {1 : 2, 3: 4, 4: 3, 2: 1, 0: 0}
# 依據值排序
sorted_x = sorted(x.items(), key=operator.itemgetter(1))
print ‘x = ‘ + str(x)
print ‘sorted_x = ‘ + str(sorted_x)
print ‘dict(sorted_x) = ‘ + str(dict(sorted_x))
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))
print ‘x = ‘ + str(x)
print ‘sorted_x = ‘ + str(sorted_x)
print ‘dict(sorted_x) = ‘ + str(dict(sorted_x))
"""
輸出:
x = {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
sorted_x = [(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)]
dict(sorted_x) = {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
x = {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
sorted_x = [(0, 0), (1, 2), (2, 1), (3, 4), (4, 3)]
dict(sorted_x) = {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
"""
Python - 字典按值(value)排序