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劍指offer42題(2)

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在網上查了另外一種方法,其實也算同一種。有一些動態規劃的思想。代碼如下:

package com.algorithm04;

public class Algorithm42_2 {
    
    public int maxSumInSubArray(int[] array){
        
        if(array.length<0)
            return 0;
        if(array.length==1)
            return array[0];
        int max,begin,end,len;
        int
[] c = new int[100]; begin = end = 0; max = 0; len = array.length; for(int i = 1 ; i < len ; i++){ if(c[i-1]>0) { c[i] = c[i-1] +array[i]; } else { c[i] = array[i]; begin
= i; } if(c[i]>max){ max = c[i]; end = i; } } return max; } public static void main(String[] args) { Algorithm42_2 algorithm42_2 = new Algorithm42_2(); int[] arrays = new
int[]{1,-2,3,10,-4,7,2,-5}; algorithm42_2.maxSumInSubArray(arrays); } }

參考http://blog.csdn.net/nciaebupt/article/details/8482077 代碼。灰常感謝!

劍指offer42題(2)