public class Solution {
    public int[] searchRange(int[] nums, int target) {
        return new int[]{binarySearch(nums,target,true),binarySearch(nums,target,false)};
    }
    private int binarySearch(int[] nums, int target, boolean mode) {
        int l=0;
        int r=nums.length-1;
        
 
while(l<r)
        {
            int m=l+(r-l)/2;
            if(nums[m]==target)
            {
                if(mode==true)
                    r=m;
                else 
                {
                    if(nums[m+1]==target)
                        l=m+1;
                    else
 

                        return m;
                }
            }
            else if(nums[m]<target)
                l=m+1;
            else
                r=m;
        }
        return l<nums.length&&nums[l]==target?l:-1;
    }
}

34. Search for a Range