LeetCode - 541. Reverse String II

阿新 • • 發佈：2017-10-22

there less clas c ++ urn then con rom append

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and left the other as original.

Example:

Input: s = "abcdefg", k = 2
Output: "bacdfeg"

Restrictions:

The string consists of lower English letters only.
Length of the given string and k will in the range [1, 10000]

class Solution {
    public String reverseStr(String s, int k) {
        StringBuilder ret = new StringBuilder();   
         
if (s.length() <= k) {
            for (int i=0; i<s.length(); i++)
                ret.append(s.charAt(s.length()-i-1));
            return ret.toString();
        }
        
        int kc = s.length() / k;
        if ((s.length() % k) != 0) kc ++;
        for (int ki=0; ki<kc; ki++) {
             
if ((ki&1)==0)
                for (int i=Math.min((ki+1)*k-1,s.length()-1); i>=ki*k; i--)
                    ret.append(s.charAt(i));
            else
                for (int i=ki*k; i<(ki+1)*k&&i<s.length(); i++)
                    ret.append(s.charAt(i));
        }
        return ret.toString();
    }
}

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