[leetcode] 190. Reverse Bits 解題報告
遞歸,註意結果的三重判斷
public boolean isBalanced(TreeNode root) { if (root==null) return true; return Math.abs(getHeight(root.left)-getHeight(root.right)) <=1 && isBalanced(root.left) && isBalanced(root.right); } public int getHeight(TreeNode node){ if (node==null){ return 0; } if (node.right == null && node.left ==null){ return 1; } return Math.max(getHeight(node.left),getHeight(node.right))+1; }
[leetcode] 190. Reverse Bits 解題報告
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[leetcode] 190. Reverse Bits 解題報告
node getheight pre logs root ever right class bit 遞歸,註意結果的三重判斷 public boolean isBalanced(TreeNode root) { if (root==null) return
[LeetCode] 190. Reverse Bits 翻轉二進制位
input repr ems return test CP 進行 post range Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represe
leetcode 190: reverse bits (go)
// abcdefgh -> efghabcd -> ghefcdab -> hgfedcba func reverseBits(n uint32) uint32 { n = (n << 16) | (n >> 16) n =((n & 0x
LeetCode#190: Reverse Bits
Description Reverse bits of a given 32 bits unsigned integer. Example Input: 43261596 Output: 964176192 Explanation: 43261596 represented
LeetCode 190.Reverse Bits (顛倒二進位制位)
顛倒給定的 32 位無符號整數的二進位制位。 示例: 輸入: 43261596 輸出: 964176192 解釋: 43261596 的二進位制表示形式為 00000010100101000001111010011100 , 返回 964176192,其二進位制表示形式為
LeetCode-190. Reverse Bits
Reverse bits of a given 32 bits unsigned integer. Example: Input: 43261596 Output: 964176192 Explanation: 43261596 represented in binary as 000000
LeetCode 190. Reverse Bits 題解
先給出最先想到的解法,java程式碼如下: public class Solution { public int reverseBits(int n) { // 將整數轉為二進位制 String binaryString = Int
leetCode 190-Reverse Bits
此題的關鍵是預先將1<<i的數字存入一個大小為32的陣列中,然後通過x & (1 << i)來獲得x的第i位是不為0的判斷.進行求和即可。 class Solution { public: Solution(){ u
LeetCode 190. Reverse Bits 顛倒二進位制位
題目:顛倒給定的 32 位無符號整數的二進位制位。示例:輸入: 43261596 輸出: 964176192 解釋: 43261596 的二進位制表示形式為 00000010100101000001111010011100 , 返回 964176192,其二進位制表
leetcode之Reverse Bits(190)
題目: 顛倒給定的 32 位無符號整數的二進位制位。 示例: 輸入: 43261596 輸出: 964176192 解釋: 43261596 的二進位制表示形式為 00000010100101000001111010011100 , 返回 964176192,
[Leetcode BY python ]190. Reverse Bits
Reverse bits of a given 32 bits unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011
LeetCode 題解之 190. Reverse Bits
190. Reverse Bits 題目描述和難度 題目描述: 顛倒給定的 32 位無符號整數的二進位制位。 示例: 輸入: 43261596 輸出: 964176192 解釋: 4326
【LeetCode-面試演算法經典-Java實現】【190-Reverse Bits(反轉二制)】
原題 Reverse bits of a given 32 bits unsigned integer. For example, given input 432
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【LeetCode】Reverse Bits 翻轉二進位制
題目 Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 000