41道題：

重要的
連表查詢
分組

制表語句：
    班級表
               Table: class
        Create Table: CREATE TABLE `class` (
          `cid` int(11) NOT NULL AUTO_INCREMENT,
          `caption` varchar(50) DEFAULT NULL,
          PRIMARY KEY (`cid`)
        ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
        
 
1 row in set (0.00 sec)

        
    學生表：
                       Table: student
        Create Table: CREATE TABLE `student` (
          `sid` int(11) NOT NULL AUTO_INCREMENT,
          `sname` varchar(50) DEFAULT NULL,
          `gender` char(10) DEFAULT NULL,
          `class_id` int(11) DEFAULT NULL,
          PRIMARY KEY (`sid`),
          KEY `fk_student_class` (`class_id`),
          CONSTRAINT `fk_student_class` FOREIGN KEY (`class_id`) REFERENCES `
 
class` (`cid`)
        ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
                

    老師表：
                       Table: teacher
        Create Table: CREATE TABLE `teacher` (
          `tid` int(11) NOT NULL AUTO_INCREMENT,
          `tname` varchar(50) DEFAULT NULL,
          PRIMARY KEY (`tid`)
        ) ENGINE
 
=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
        1 row in set (0.00 sec)
                        
                        
    課程表：
                      Table: course
        Create Table: CREATE TABLE `course` (
          `cid` int(11) NOT NULL AUTO_INCREMENT,
          `cname` char(25) DEFAULT NULL,
          `teacher_id` int(11) DEFAULT NULL,
          PRIMARY KEY (`cid`),
          KEY `fk_course_teacher` (`teacher_id`),
          CONSTRAINT `fk_course_teacher` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`tid`)
        ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
        1 row in set (0.00 sec)

    成績表：    
            
        create table score
             (sid int not null auto_increment primary key,
              student_id int not null,
             corse_id int not null,
             number int not null,
             unique uq_sc (student_id,corse_id),
             
             CONSTRAINT fk_sc_st FOREIGN key (student_id) REFERENCES student(sid),
             constraint fk_sc_co foreign key  (corse_id) references course(cid)
             ) engine=innodb default charset=utf8;
            
            
    group by前面的slect 只能用聚合函數count,max什麽的     
    
    
v= 111 if 1==1 else 110 三元運算符
#########################################################
作業練習：
    http://www.cnblogs.com/wupeiqi/articles/5729934.html    
            
            
http://www.cnblogs.com/wupeiqi/p/5748496.html  參考答案            
            
##########################################################

用到的知識點
- 臨時表
        select * from (select * from tb where id< 10) as B;
        
    --- 
        select 
            id,
            name,
            1,
            (select count(1) from tb)----只要拿到的是一個值就可以
        from tb2
    ---把最外層的表s1，每次循環取一個常量值再到每一列中再循環一次    
        SELECT 
            student_id,
            (select num from score as s2 where s2.student_id=s1.student_id and course_id = 1) as 語文,
            (select num from score as s2 where s2.student_id=s1.student_id and course_id = 2) as 數學,
            (select num from score as s2 where s2.student_id=s1.student_id and course_id = 3) as 英語
        from score as s1;            

    ----avg(if(isnull(score.num),0,score.num))
         三目運算符
            
#####################################################
具體作業：
    1、自行創建測試數據

2、查詢“生物”課程比“物理”課程成績高的所有學生的學號；
    PS：查出生物課程的學生，查出物理課程的學生，用臨時表，再連接查詢
        select A.student_id from 
        (select * from score 
        LEFT JOIN course on score.course_id=course.cid
        where course.cname="生物"
        ) as A
        LEFT JOIN  
        (select * from score 
        LEFT JOIN course on score.course_id=course.cid
        where course.cname="物理"
        ) as B 
        on A.student_id=B.student_id
        where A.num> B.num

3、查詢平均成績大於60分的同學的學號和平均成績； 
    select student_id, avg(num) from score GROUP BY student_id
    PS:把名字也帶上
    select S.student_id,student.sname,S.av_s from 
    (SELECT student_id, avg(num) AS av_s FROM score GROUP BY student_id HAVING av_s > 60) as S
    LEFT JOIN student on student.sid=S.student_id

4、查詢所有同學的學號、姓名、選課數、總成績；
    SELECT score.student_id,student.sname, COUNT(score.student_id),sum(score.num) from score 
    LEFT JOIN student ON score.student_id=student.sid
    GROUP BY score.student_id

5、查詢姓“李”的老師的個數；
    select COUNT(*) from teacher where teacher.tname 
    LIKE "李%"

6、查詢沒學過“李平老師“課的同學的學號、姓名；
    PS：先查找李平的課程ID，再到score表中找學他的課的學生Id，再去student表中全部排除
    select student.sid,student.sname from student
    where student.sid not in 
    (
    select score.student_id from score
    where course_id in (select course.cid from course
    LEFT JOIN teacher on teacher.tid=course.cid
    where teacher.tname="李平老師")
    )

7、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名；
    PS：找出score表中學過課程1，或者2，或者1,2的學生，分組找出大於2的，再與學生表進行連接查詢
    select student.sid,student.sname from score
    LEFT JOIN  student on score.student_id=student.sid
     where score.course_id=1 or score.course_id=2 GROUP BY score.student_id HAVING count(score.course_id)>1

8、查詢學過“葉平”老師所教的所有課的同學的學號、姓名；
    PS：語句分兩部分B表是查出學過葉平老師所有課程的學生ID（註意其中葉平的課程有所變化所以不能count >2）
         再與學生表進行關聯
    SELECT student.sid,student.sname FROM student
    LEFT JOIN 
        (
            SELECT score.student_id FROM score WHERE score.course_id 
                IN (
                    SELECT cid FROM course
                    LEFT JOIN teacher ON teacher.tid = course.teacher_id
                    WHERE teacher.tname = "李平老師"
                   ) --查出葉平老師所教的課程的ID 
            GROUP BY score.student_id
            HAVING
                count(score.student_id) = 
                ( 
                    SELECT count(cid) FROM course LEFT JOIN teacher ON teacher.tid = course.teacher_id
                    WHERE teacher.tname = "李平老師" 
                )        --查出葉平老師總共教了幾門課count(cid)
        ) AS B             --查出學過葉平老師所有課程的學生ID
    ON student.sid = B.student_id


9、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名；
    PS:
        select student.sid,student.sname from student
        left JOIN 
            (select A.student_id from 
                    (select * from score 
                    LEFT JOIN course on score.course_id=course.cid
                    where course.cid=1
                    ) as A
                    LEFT JOIN  
                    (select * from score 
                    LEFT JOIN course on score.course_id=course.cid
                    where course.cid=2
                    ) as B 
                    on A.student_id=B.student_id
                    where A.num<B.num 
            ) as C 
        on student.sid=C.student_id

10、查詢有課程成績小於60分的同學的學號、姓名；
        select sid,sname from student where sid in (
        select distinct student_id from score where num < 60
    )

11、查詢沒有學全所有課的同學的學號、姓名；
    PS ---count要嘛用1要嘛用主鍵，效率高
    SELECT student.sid,student.sname from student
    INNER JOIN 
     (
        select score.student_id,count(1) from score GROUP BY score.student_id HAVING count(1) < (SELECT count(cid) from course)
     ) as B
    on student.sid = B.student_id

12、查詢至少有一門課與學號為“001”的同學所學相同的同學的學號和姓名；
    select student.sid,student.sname from student
    INNER JOIN
    (
    SELECT score.student_id,score.course_id from score where score.student_id !=1 
    and  score.course_id in (select score.course_id from score where score.student_id=1) GROUP BY score.student_id
    ) as B
    on student.sid=B.student_id

13、查詢至少學過學號為“001”同學所有課的其他同學學號和姓名
    select student.sid,student.sname from student
    INNER  JOIN
    (
        SELECT score.student_id,count(1) from score where score.student_id !=1 
            and  score.course_id in (select score.course_id from score where score.student_id=1) 
        GROUP BY score.student_id 
        HAVING count(1) = (select count(1) from score where score.student_id=1)
        ) AS B
    on student.sid=B.student_id

14、查詢和“002”號的同學學習的課程完全相同的其他同學學號和姓名；
    SELECT student_id from score where student_id 
    in (
        select student_id from score where student_id !=2 GROUP BY student_id 
            HAVING COUNT(1) =(select count(1) from score where student_id=1)
        ) 
    and course_id in (SELECT course_id from score where student_id =2) 
    GROUP BY student_id HAVING COUNT(1) = (SELECT count(1) from score where student_id)

15、刪除學習“葉平”老師課的SC表記錄；
    delete from score where course_id in 
    (
      select cid from course left join teacher on course.teacher_id = teacher.tid where teacher.name = ‘葉平‘
    )

16、向SC表中插入一些記錄，這些記錄要求符合以下條件：①沒有上過編號“002”課程的同學學號；②插入“002”號課程的平均成績； 
    insert into score(student_id,course_id,num) 
    VALUES(select student_id,2,(select AVG(num) from score where course_id = 2) from score where course_id !=2) 

17、按平均成績從低到高顯示所有學生的“語文”、“數學”、“英語”三門的課程成績，按如下形式顯示： 學生ID,語文,數學,英語,有效課程數,有效平均分；
       select s1.student_id,
       (select num from score left join course on score.course_id = course.cid where course.cname = "生物" and score.student_id=s1.student_id) as 生物,
        (select num from score left join course on score.course_id = course.cid where course.cname = "物理" and score.student_id=s1.student_id) as 物理,
        (select num from score left join course on score.course_id = course.cid where course.cname = "體育" and score.student_id=s1.student_id) as 體育,
        count(s1.course_id),
        avg(s1.num)
    from score as s1
    group by student_id desc

18、查詢各科成績最高和最低的分：以如下形式顯示：課程ID，最高分，最低分；
    SELECT course_id,MAX(num),min(num) from score GROUP BY course_id

19、按各科平均成績從低到高和及格率的百分數從高到低順序；

            select 
        course_id,avg(num),
        sum(case when num <60 THEN 0 ELSE 1 END),sum(1),
        sum(case when num <60 THEN 0 ELSE 1 END)/sum(1) as jgl 
        from score GROUP BY course_id order by AVG(num) asc,jgl desc;

20、課程平均分從高到低顯示（現實任課老師）；
        select 
        course_id,avg(num),teacher.tname 
        from score
        LEFT JOIN course on score.course_id=course.cid
        left JOIN teacher on teacher.tid = course.teacher_id
        GROUP BY course_id desc
        
         select avg(if(isnull(score.num),0,score.num)),teacher.tname from course
    left join score on course.cid = score.course_id
    left join teacher on course.teacher_id = teacher.tid
 
    group by score.course_id

21、查詢各科成績前三名的記錄:(不考慮成績並列情況) 

22、查詢每門課程被選修的學生數；
SELECT student_id ,count(1) from score GROUP BY course_id HAVING COUNT(1) >5

23、查詢出只選修了一門課程的全部學生的學號和姓名；
SELECT  student.sid,student.sname from student
INNER  JOIN 
(SELECT student_id ,count(1) from score GROUP BY student_id HAVING COUNT(1) =1) as B
on student.sid=B.student_id

24、查詢男生、女生的人數；
SELECT gender,COUNT(1) from student GROUP BY gender

25、查詢姓“張”的學生名單；
SELECT sname from student where sname LIKE "張%"

26、查詢同名同姓學生名單，並統計同名人數；
SELECT sname,count(1) from student GROUP BY sname

27、查詢每門課程的平均成績，結果按平均成績升序排列，平均成績相同時，按課程號降序排列；
SELECT course_id,AVG(num) from score GROUP BY score.course_id ORDER BY avg(num) ASC,course_id DESC

28、查詢平均成績大於85的所有學生的學號、姓名和平均成績；
SELECT sid,sname,T.B from student
INNER  JOIN
(SELECT student_id ,avg(if(ISNULL(num) ,0,num)) as B from score GROUP BY student_id HAVING B >85) as T
on T.student_id=student.sid

29、查詢課程名稱為“生物”，且分數低於60的學生姓名和分數；
    SELECT student.sname,score.num from course
    LEFT JOIN score on course.cid=score.course_id
    LEFT JOIN student on student.sid=score.student_id
     
    where course.cname=‘生物‘ and score.num < 60

30、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名；

    SELECT student.sname,score.num from course
    LEFT JOIN score on course.cid=score.course_id
    LEFT JOIN student on student.sid=score.student_id
    where course.cid=3 and score.num >80 

31、求選了課程的學生人數
SELECT count(DISTINCT(score.student_id)) from score

32、查詢選修“李平”老師所授課程的學生中，成績最高的學生姓名及其成績；

SELECT student.sname,T.num from student
INNER  JOIN 
(SELECT * from teacher 
LEFT JOIN course on teacher.tid=course.teacher_id
LEFT JOIN score on score.course_id=course.cid
 GROUP BY num HAVING teacher.tname="張磊老師"  ORDER BY  num DESC LIMIT 0,1) as T
on student.sid= T.student_id

33、查詢各個課程及相應的選修人數；
 select course.cname,count(1) from score
    left join course on score.course_id = course.cid
    group by course_id;

34、查詢不同課程但成績相同的學生的學號、課程號、學生成績；
SELECT DISTINCT s1.student_id,s1.course_id,s1.num from score as s1,score as s2 WHERE s1.sid !=s2.sid and s1.course_id !=s2.course_id and s1.num=s2.num

35、查詢每門課程成績最好的前兩名；
 select score.sid,score.course_id,score.num,T.first_num,T.second_num from score left join
    (
    select
        sid,
        (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 0,1) as first_num,
        (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 1,1) as second_num
    from
        score as s1
    ) as T
    on score.sid =T.sid
    where score.num <= T.first_num and score.num >= T.second_num

36、檢索至少選修兩門課程的學生學號；
SELECT student_id from score GROUP BY student_id HAVING count(student_id) >1

37、查詢全部學生都選修的課程的課程號和課程名；

38、查詢沒學過“葉平”老師講授的任一門課程的學生姓名；
    PS：先查出學過李平老師任意一門課的學生，包括只選了一門的，然後，全部排除
    SELECT student.sid from student
    WHERE sid not in(
    SELECT score.student_id from score
    WHERE course_id in
    (
    SELECT  course.cid from course
     LEFT JOIN teacher on course.teacher_id=teacher.tid WHERE teacher.tname="李平老師"
     ))

39、查詢兩門以上不及格課程的同學的學號及其平均成績；
 select student_id,count(1) from score where num < 60 group by student_id having count(1) > 2

40、檢索“004”課程分數小於60，按分數降序排列的同學學號；
   select student_id from score where num< 60 and course_id = 4 order by num desc;

41、刪除“002”同學的“001”課程的成績；
    delete from score where course_id = 1 and student_id = 2

第四天(41道題全解)