[LeetCode]Path Sum系列
1.二叉樹路徑求指定和,需要註意的是由於有負數,所以即使發現大於目標值也不能返回false,而且返回true的條件有兩個,到葉節點且等於sum,缺一不可
public boolean hasPathSum(TreeNode root, int sum) { if (root==null) return false; if (root.val==sum&&root.left==null&&root.right==null) return true; else return hasPathSum(root.left,sum-root.val)||hasPathSum(root.right,sum- root.val); }
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[LeetCode]Path Sum系列
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