A - Higher Math (LightOJ - 1053)
- 題目大意
給出三個數判斷能否構成一個直角三角形。
- 解題思路
直接用勾股定理判斷即可。(註意輸出格式!!!)
- 代碼
#include<iostream> using namespace std; int main() { long long n, a, b, c; cin >> n; for (int i = 0; i<n; i++) { cin >> a >> b >> c; cout << "Case " << i + 1 << ": "; if ((a*a +b*b==c*c) || (a * a + c * c == b * b) || (b * b + c * c == a * a)) cout << "yes" << endl; else cout << "no" << endl; } return 0; }
A - Higher Math (LightOJ - 1053)
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