1. 程式人生 > >125. Valid Palindrome(判斷忽略標點的字符串是否回文,加個正則,與上一題解法一樣)

125. Valid Palindrome(判斷忽略標點的字符串是否回文,加個正則,與上一題解法一樣)

purpose ane define note nbsp import ase solution amp

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

 1 class Solution:
 2     def isPalindrome(self, s):
 3         """
 4         :type s: str
 5         :rtype: bool
 6         """
 7         if s==‘‘:
 8             return True
 9         import re
10         x = re.sub(
\W,‘‘,s).lower() 11 if x==‘‘: 12 return True 13 if(len(x)%2!=0):# 14 for i in range(int(len(x)/2)+1): 15 if(x[i]!=x[len(x)-i-1]): 16 return False 17 else: 18 for i in range(int(len(x)/2)+1): 19 if
(x[i]!=x[len(x)-i-1]): 20 return False 21 return True 22

125. Valid Palindrome(判斷忽略標點的字符串是否回文,加個正則,與上一題解法一樣)