1. 程式人生 > >使多個線程循環輸出0-99-0-99

使多個線程循環輸出0-99-0-99

imp lba 順序 圖片 his AC sign rto toolbar

直接上代碼,後面我也有一個問題,關於對象的notifyAll或者notify或者single或者singleAll,喚醒線程是順序喚醒嗎,我這裏都是順序輸出了

關於公平與非公平鎖的問題?喚醒是公平的???又沒有大佬幫助解答!

技術分享圖片
 1 import java.util.concurrent.LinkedBlockingQueue;
 2 import java.util.concurrent.ThreadPoolExecutor;
 3 import java.util.concurrent.TimeUnit;
 4 import java.util.concurrent.locks.Condition;
 5 import java.util.concurrent.locks.Lock;
 6 import java.util.concurrent.locks.ReentrantLock;
 7 
 8 /**
 9  * 使用lock對象,使多個線程循環輸出0-99-0-99
10  */
11 public class AandBforTOthreadLock {
12     private static Lock lock=new ReentrantLock();
13     private static Condition single=lock.newCondition();
14     static class A implements Runnable{
15         private int i=0;
16         public A(int i){
17             this.i=i;
18         }
19         @Override
20         public void run() {
21             try {
22                 lock.lock();
23                 while (true){
24                     System.out.println(i);
25                     single.await();
26                     single.signal();
27                 }
28             }catch (Exception e){
29                 e.printStackTrace();
30             }finally {
31                 lock.unlock();
32             }
33         }
34     }
35     static class B implements Runnable{
36         @Override
37         public void run() {
38             try {
39                 lock.lock();
40                 while (true){
41                     System.out.println("99");
42                     single.signalAll();
43                     single.await();
44                 }
45             }catch (Exception e){
46                 e.printStackTrace();
47             }finally {
48                 lock.unlock();
49             }
50         }
51     }
52 
53     public static void main(String[] args) throws InterruptedException {
54         ThreadPoolExecutor threadPoolExecutor=new ThreadPoolExecutor(100,100,0L, TimeUnit.MILLISECONDS,
55                 new LinkedBlockingQueue<Runnable>());
56         for (int i=0;i<99;i++){
57             threadPoolExecutor.execute(new A(i));
58             Thread.sleep(3l);
59         }
60         Thread.sleep(10000l);
61         threadPoolExecutor.execute(new B());
62     }
63 
64 }
輸出:
技術分享圖片

……

技術分享圖片


使多個線程循環輸出0-99-0-99