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Redis訂閱&釋出以及python程式碼實現

A:命令列 伺服器端 192.168.1.168:7000> subscribe foo bar Reading messages... (press Ctrl-C to quit) 1) "subscribe" 2) "redisChat" 3) (integer) 1 1 1) "message" 2) "redisChat" 3) "hello!" 1) "message" 2) "redisChat" 3) "my name is alex!"
客戶端 127.0.0.1:7000> publish foo  "hello!" (integer) 1 127.0.0.1:7000> publish bar "my name is alex!" (integer) 1 127.0.0.1:7000> publish bar "我是中文!" (integer) 1 127.0.0.1:7000> 
B:叢集Python pip install redis-py-cluster

--------------------------------------------------------------- 伺服器端
from rediscluster import StrictRedisCluster
startup_nodes = [{"host": "192.168.1.168", "port": "7000"}]
rc = StrictRedisCluster(startup_nodes=startup_nodes, decode_responses=True)
ps=rc.pubsub()
ps.subscribe(['foo'
, 'bar'])
for item in ps.listen():
if item['type'] == 'message':
print item['data']
客戶端
from rediscluster import StrictRedisCluster
startup_nodes = [{"host": "192.168.1.168", "port": "7000"}]
rc = StrictRedisCluster(startup_nodes=startup_nodes, decode_responses=True)
ps = rc.pubsub()
ps.subscribe(['foo'
, 'bar'])
rc.publish('foo', 'hello foo')
rc.publish('bar', 'hello bar')

 
  
 C:非叢集python 
 
  pip install redis
  
-------------------------------------------------------------
import redis
rc = redis.Redis(host='127.0.0.1')
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
for item in ps.listen():
if item['type'] == 'message':
print item['data']

import redis
rc = redis.Redis(host='127.0.0.1')
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
rc.publish('foo', 'hello foo')
rc.publish('bar', 'hello bar')