java+Quartz實現定時任務
阿新 • • 發佈:2018-11-28
1、首先:匯入quartz相關的jar包,這裡我用的是maven構建的專案,pom.xml檔案匯入如下:
<dependency> <groupId>org.quartz-scheduler</groupId> <artifactId>quartz</artifactId> <version>2.2.1</version> </dependency> <dependency> <groupId>org.quartz-scheduler</groupId> <artifactId>quartz-jobs</artifactId> <version>2.2.1</version> </dependency>
2、定義要進行定時任務類(該類實現了Quartz 下的job類):
import org.quartz.Job; import org.quartz.JobExecutionContext; import org.quartz.JobExecutionException; public class MyJob implements Job { @Override public void execute(JobExecutionContext arg0) throws JobExecutionException {// TODO Auto-generated method stub System.out.println("開啟了定時任務"); } }
3、接下來要做的就是按照定時任務的固定步驟來做即可:1:定義排程器並且開啟 2:定義任務器 3:定義觸發器 4 註冊
import org.quartz.*; import org.quartz.impl.StdSchedulerFactory; public class QuartzDemo { public staticvoid main(String[] args) { try { new QuartzDemo().quartzTest(); } catch (InterruptedException i) { i.printStackTrace(); } } public void quartzTest() throws InterruptedException{ try { //獲取排程器 Scheduler scheduler = StdSchedulerFactory.getDefaultScheduler(); scheduler.start(); //建立任務器:定義任務細節 JobDetail jobDetail = JobBuilder.newJob(MyJob.class).withIdentity("job1", "group1").build(); ScheduleBuilder scheduleBuilder =SimpleScheduleBuilder.simpleSchedule().withIntervalInSeconds(5).repeatForever(); //定義觸發器 Trigger trigger=TriggerBuilder.newTrigger().withIdentity("simpleTrigger", "simpleTriggerGroup") .withSchedule(scheduleBuilder).startNow().build(); //將任務和觸發器註冊到排程器中 scheduler.scheduleJob(jobDetail, trigger); // Thread.sleep(1000*30); } catch (SchedulerException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }