【資料庫】MySQL相關操作
阿新 • • 發佈:2018-12-09
--批量插入資料 insert into actor (actor_id, first_name, last_name, last_update) values (1,'PENELOPE','GUINESS','2006-02-15 12:34:33'),(2,'NICK','WAHLBERG','2006-02-15 12:34:33'); --找出所有員工當前(to_date='9999-01-01')具體的薪水salary情況,對於相同的薪水只顯示一次,並按照逆序顯示 select distinct salary from salaries where to_date='9999-01-01' order by salary desc; --查詢最晚入職員工的所有資訊 select *from employees order by hire_date desc limit 0,1; select *from employees where hire_date in (select max(hire_date) from employees); select *from employees where hire_date = (select max(hire_date) from employees); --查詢入職員工時間排名倒數第三的員工所有資訊 select *from employees order by hire_date desc limit 2,1; --查詢薪水漲幅超過15次的員工號emp_no以及其對應的漲幅次數t select emp_no, count(emp_no) as t from salaries group by emp_no having t>15; --獲取所有部門當前manager的當前薪水情況,給出dept_no, emp_no以及salary,當前表示to_date='9999-01-01' select dept_manager.dept_no, dept_manager.emp_no, salaries.salary from dept_manager, salaries where dept_manager.emp_no = salaries.emp_no and dept_manager.to_date = '9999-01-01' and salaries.to_date = '9999-01-01'; --從titles表獲取按照title進行分組,每組個數大於等於2,給出title以及對應的數目t select title, count(emp_no) as t from titles group by title having t>=2; --Write a SQL query to find all duplicate emails in a table named Person.(編寫一個SQL查詢來查詢名為“人”的表中的所有重複郵件) select email from person group by emial having count(email)>1; --Write a SQL solution to output big countries' name, population and area.(編寫一個SQL解決方案,輸出大國的名字、人口和地區) select name, population, area from world where area>3000000 and population>25000000; select name, population, area from world where area>3000000 union select name, population, area from world where population>25000000; --Write a SQL query to get the nth highest salary from the Employee table(編寫SQL查詢,從僱員表中獲得第N個最高工資) set M=N-1; select distinct salary from Employee order by desc limit M,1;