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1083 List Grades(set,運算子過載)

1083 List Grades (25 分)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format: N name[1] ID[1] grade[1] name[2] ID[2] grade[2] … … name[N] ID[N] grade[N] grade1 grade2 where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.

Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
分析

本題本質上在考察結構體的排序,但是set在生成的過程是有序的,因此,我們只需過載>運算子,並且在定義set時指定是按照less排序還是按照greater排序。

#include <iostream>
#include
<set>
using namespace std; struct node { string name,id; int score; }; bool operator>(const node &a,const node &b) { return a.score>b.score; } set<node,greater<node> >s; int main() { int n,g1,g2; cin>>n; for(int i=0; i<n; i++) { string name,id; int score; cin>>name>>id>>score; s.insert(node {name,id,score}); } cin>>g1>>g2; bool flag=false; for (auto t : s) { if(g1<=t.score && t.score<=g2) { cout<<t.name<<" "<<t.id<<endl; flag=true; } } if(!flag) cout<<"NONE"<<endl; return 0; }