You are given a string representing an attendance record for a student. The record only contains the following three characters: ‘A’ : Absent. ‘L’ : Late. ‘P’ : Present. A student could be rewarded if his attendance record doesn’t contain more than one ‘A’ (absent) or more than two continuous ‘L’ (late). You need to return whether the student could be rewarded according to his attendance record. Example 1:

Input: "PPALLP" 
Output: True 

Example 2:

Input: "PPALLL"
Output: False

解釋： python程式碼：

class Solution(object):
    def checkRecord(self, s):
        """
        :type s: str
        :rtype: bool
        """
        if  s.count('A')>1 or s.count('LLL')>0:
            return False
        return
 
 True

c++程式碼：

class Solution {
public:
    bool checkRecord(string s) {
        if(count(s.begin(),s.end(),'A')>1 || s.find("LLL")!=string::npos)
            return false;
        return true;
    }
};

總結： 學會使用c++ <string>中的count()函式和find()函式。