1. 程式人生 > >資料結構 筆記:雙向連結串列的實現

資料結構 筆記:雙向連結串列的實現

單鏈表的另一個缺陷

-單向性

·只能從頭結點開始高效訪問連結串列中的資料元素

-缺陷

·如果需要逆向訪問單鏈表中的資料元素將極其低效

雙向的線性表

-在“單鏈表”的結點中增加一個指標pre,用於指向當前結點的前驅結點

雙向連結串列的繼承層次結構

DualLinkList的定義

template<typename T>
class DualLinkList : public List<T>
{
protected:
    struct Node :public Object
    {
        T value;
        Node* next;
        Node* pre;
    };

    mutable
//    struct{
//        char reserved[sizeof(T)];
//        Node* next;
//    }
    Node
    m_header;

    Node* position(int i) const
    {
        Node* ret = reinterpret_cast<Node*>(&m_header);

        for(int p=0;p<i;p++)
        {
            ret = ret->next;
        }
        return ret;
    }

    virtual Node* create()
    {
        return new Node();
    }

    virtual void destroy(Node* pn)
    {
        delete pn;
    }

    int m_step;
    Node* m_current;
    int m_length;
public:
    DualLinkList()
    {
        //m_header.reserved("nul");
        m_header.next = NULL;
        m_header.pre = NULL;
        m_step = 1;
        m_current = NULL;
        m_length = 0;
    }
    virtual bool insert(const T& e)
    {
        return insert(m_length,e);
    }

    virtual bool insert(int i,const T& e)
    {
        bool ret = ((0 <= i) && (i <= m_length));

        if(ret)
        {
            Node* node = create();
            if( node != NULL)
            {
                Node *current = position(i);
                Node* next = current->next;
                //Node* pre = current->pre;
                //qDebug() << current;

                node->value = e;

                node->next = current->next;
                current->next = node;
                //qDebug() << "i = " << i <<" , e = " << e << "  " << m_length;
                if(current != reinterpret_cast<Node*>(&m_header))
                {
                    //qDebug() << 1;
                    node->pre = current;
                    next->pre = NULL;
                }
                else
                {
                    //qDebug() << 2;
                    node->pre = NULL;
                }


                if(next != NULL)
                {
                    //qDebug() << 4;
                    next->pre = node;
                }
                //qDebug() << 5;
                m_length++;
            }
            else
            {
                //丟擲異常
                //qDebug() << "錯錯了";
            }
        }
        return ret;
    }
    virtual bool remove(int i)
    {
        bool ret = ((0 <= i) && (i < m_length));

        if(ret)
        {
            Node* current = position(i);

            Node* toDel = current->next;
            Node* next = toDel->next;
            if(m_current == toDel)
            {
                m_current = next;
            }
            current->next = next;

            if(next != NULL)
            {
                next->pre = toDel->pre;
            }

            m_length--;
            destroy(toDel);
        }
        return ret;
    }

    virtual bool set(int i,const T& e)
    {
        bool ret = ((0 <=i ) && (i < m_length));

        if(ret)
        {
            Node* current = position(i);

            current->next->value = e;
        }
        return ret;
    }

    virtual T get(int i) const
    {
        T ret;

        if(get(i,ret))
        {
            return ret;
        }
        else
        {
            //丟擲異常
            //qDebug() << "錯了";
        }

    }
    virtual bool get(int i, T& e) const
    {
        bool ret = ((0 <=i ) && (i < m_length));

        if(ret)
        {
            Node* current = position(i);
            e = current->next->value;
            //qDebug() << e;
        }
        return ret;
    }
    virtual int length() const
    {
        return m_length;
    }

    int find (const T& e) const
    {
        int ret = -1;
        int i = 0;
        Node* node = m_header.next;

        while(node)
        {
            if(node->value == e)
            {
                ret = i;
                break;
            }
            else
            {
                node = node->next;
                i++;
            }
        }
        return ret;
    }
    virtual void clear()
    {
        while(m_length > 0)
        {
            remove(0);
        }

        m_length = 0;
    }

    virtual bool move(int i,int step = 1)
    {
        bool ret = (0 <= i)&& (i< m_length) && (step >0);

        if(ret)
        {
            m_current = position(i)->next;
            m_step = step;
        }
        return ret;
    }

    virtual bool end()
    {
        return (m_current == NULL);
    }

    virtual T current()
    {
        if(!end())
        {
            return m_current->value;
        }
        else
        {
            //丟擲異常
        }
    }

    virtual bool next()
    {
        int i  = 0;
        while((i < m_step) && !end())
        {
            m_current = m_current->next;
            i++;
        }
        return (i == m_step);
    }

    virtual bool pre()
    {
        int i  = 0;
        while((i < m_step) && !end())
        {
            m_current = m_current->pre;
            i++;
        }
        return (i == m_step);
    }

    ~DualLinkList()
    {
        clear();
    }
};

總結:

-雙向連結串列是為了彌補單鏈表的缺陷而重新設計的

-再概念上,雙向連結串列不是單鏈表,沒有繼承關係

-雙向連結串列中的遊標能夠直接訪問當前結點的前驅和後繼

-雙向連結串列是線性表概念的最終實現(更貼近理論上的線性表)