有橫向的條形碼,也有豎直方向的條形碼.

怎麼把條形碼豎起來呢?

1.旋轉裝著條形碼的view

此方法不可行 因為view的寬高和二維碼的bitmap的寬高是相反的啊.這樣的話即使旋轉了,view裡顯示的圖形會非常小.不行.

2.生成條形碼的bitmap的時候,就要寬高和容器寬高一致.

此方法可行,只要在生成條形碼bitmap之後,逆時針旋轉90度,得到新的bitmap就行了.

程式碼:

public static Bitmap getBarcodeBitmapVertical(String content, int qrWidth, int qrHeight) {
    //文字的高度
    int mHeight = qrHeight / 4;
    try {
        Map<EncodeHintType, Object> hints = new EnumMap(EncodeHintType.class);
        hints.put(EncodeHintType.CHARACTER_SET, "utf-8");
        hints.put(EncodeHintType.ERROR_CORRECTION, ErrorCorrectionLevel.H);
        hints.put(EncodeHintType.MARGIN, 1);
        BitMatrix result;
        try {
            result = new MultiFormatWriter().encode(content, BarcodeFormat.CODE_128, qrWidth, mHeight * 3, hints);
        } catch (IllegalArgumentException iae) {
            return null;
        }
        int width = result.getWidth();
        int height = result.getHeight();
        int[] pixels = new int[width * height];
        for (int y = 0; y < height; y++) {
            int offset = y * width;
            for (int x = 0; x < width; x++) {
                pixels[offset + x] = result.get(x, y) ? BLACK : 0;
            }
        }

        Bitmap qrBitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
        qrBitmap.setPixels(pixels, 0, width, 0, 0, width, height);
        //大的bitmap
        Bitmap bigBitmap = Bitmap.createBitmap(width, qrHeight, Bitmap.Config.ARGB_8888);

        Canvas canvas = new Canvas(bigBitmap);
        Rect srcRect = new Rect(0, 0, width, height);
        Rect dstRect = new Rect(0, 0, width, height);
        canvas.drawBitmap(qrBitmap, srcRect, dstRect, null);

        Paint p = new Paint();
        p.setColor(Color.BLACK);
        p.setFilterBitmap(true);
        p.setTextSize(mHeight);
        canvas.translate(width / 10, mHeight);
        canvas.drawText(content, 0, content.length(), 0, height, p);
        canvas.save();
        //旋轉
        Matrix matrix = new Matrix();
        matrix.setRotate(-90, (float) bigBitmap.getWidth() / 2, (float) bigBitmap.getHeight() / 2);
        Bitmap dstbmp = Bitmap.createBitmap(bigBitmap, 0, 0, bigBitmap.getWidth(), bigBitmap.getHeight(),
                matrix, true);
        return dstbmp;
    } catch (Exception e) {
        LogUtil.d("bitmap 旋轉失敗!");
        return null;
    }
}