要排序ArrayList你可以用
Collections.sort() 這個static方法

例：
import java.util.*;
public class Jtest {
public static void main(String[] args) {
//初始化ArrayList
ArrayList<String> myList = new ArrayList<String>();
myList.add(“Balance”);
myList.add(“Apple”);
myList.add(“Design”);
myList.add(“Center”);

//將排序前的資料顯示出來
System.out.println(“排序前：”);
for (String str : myList) {
System.out.println(str);
}

//進行排序
Collections.sort(myList);
System.out.println(“\n”);

//將排序後的資料顯示出來
System.out.println(“排序後：”);
for (String str : myList) {
System.out.println(str);
}
}
}

執行結果：

排序前：
Balance
Apple
Design
Center

排序後：
Apple
Balance
Center
Design

Following on from our introduction to sorting in Java, we consider here one of the simplest cases of sorting a List

List<String> words = new ArrayList<String>(50);
words.add("once");
words.add("upon");
words.add("a");
words.add("time");
...

Now, we can sort this list with a simple call to the following library method:

Collections.sort(words);

The Collections.sort() method will work “out of the can” on lists of various “basic” objects that you’d expect to be able to sort, including instances of Number– the primitive wrapper classes Integer, Long, Float etc plus BigInteger and BigDecimal.

Sorting an array

Sorting an array of these objects is just as easy¹:

Arrays.sort(myArray);

The above method takes an array of objects, but the Arrays class also provides similar methods for sorting primitive arrays.