java工具類 六 根據經緯度計算距離
阿新 • • 發佈:2018-12-29
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Java實現根據經緯度計算距離
在項目開發過程中,需要根據兩地經緯度坐標計算兩地間距離,所用的工具類如下:
Demo1:
public static double getDistatce(double lat1, double lat2, double lon1, double lon2) {
double R = 6371;
double distance = 0.0;
double dLat = (lat2 - lat1) * Math.PI / 180;
double dLon = (lon2 - lon1) * Math.PI / 180 ;
double a = Math.sin(dLat / 2) * Math.sin(dLat / 2)
+ Math.cos(lat1 * Math.PI / 180)
* Math.cos(lat2 * Math.PI / 180) * Math.sin(dLon / 2)
* Math.sin(dLon / 2);
distance = (2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a))) * R;
return distance;
}
Demo2:
private static final double EARTH_RADIUS = 6378.137 * 1000;
private static double rad(double d)
{
return d * Math.PI / 180.0;
}
public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
{
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double a = radLat1 - radLat2;
double b = rad(lng1) - rad(lng2);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2) +
Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));
s = s * EARTH_RADIUS ;
s = Math.round(s * 10000) / 10000;
return s;
}
Demo3:
private static final double EARTH_RADIUS = 6378137;//赤道半徑(單位m)
/**
* 轉化為弧度(rad)
* */
private static double rad(double d)
{
return d * Math.PI / 180.0;
}
/**
* 基於余弦定理求兩經緯度距離
* @param lon1 第一點的精度
* @param lat1 第一點的緯度
* @param lon2 第二點的精度
* @param lat3 第二點的緯度
* @return 返回的距離,單位km
* */
public static double LantitudeLongitudeDist(double lon1, double lat1,double lon2, double lat2) {
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double radLon1 = rad(lon1);
double radLon2 = rad(lon2);
if (radLat1 < 0)
radLat1 = Math.PI / 2 + Math.abs(radLat1);// south
if (radLat1 > 0)
radLat1 = Math.PI / 2 - Math.abs(radLat1);// north
if (radLon1 < 0)
radLon1 = Math.PI * 2 - Math.abs(radLon1);// west
if (radLat2 < 0)
radLat2 = Math.PI / 2 + Math.abs(radLat2);// south
if (radLat2 > 0)
radLat2 = Math.PI / 2 - Math.abs(radLat2);// north
if (radLon2 < 0)
radLon2 = Math.PI * 2 - Math.abs(radLon2);// west
double x1 = EARTH_RADIUS * Math.cos(radLon1) * Math.sin(radLat1);
double y1 = EARTH_RADIUS * Math.sin(radLon1) * Math.sin(radLat1);
double z1 = EARTH_RADIUS * Math.cos(radLat1);
double x2 = EARTH_RADIUS * Math.cos(radLon2) * Math.sin(radLat2);
double y2 = EARTH_RADIUS * Math.sin(radLon2) * Math.sin(radLat2);
double z2 = EARTH_RADIUS * Math.cos(radLat2);
double d = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)+ (z1 - z2) * (z1 - z2));
//余弦定理求夾角
double theta = Math.acos((EARTH_RADIUS * EARTH_RADIUS + EARTH_RADIUS * EARTH_RADIUS - d * d) / (2 * EARTH_RADIUS * EARTH_RADIUS));
double dist = theta * EARTH_RADIUS;
return dist;
}
Demo4:
//google map
private static final double EARTH_RADIUS = 6378137;//赤道半徑(單位m)
/**
* 轉化為弧度(rad)
* */
private static double rad(double d)
{
return d * Math.PI / 180.0;
}
/**
* 基於googleMap中的算法得到兩經緯度之間的距離,計算精度與谷歌地圖的距離精度差不多,相差範圍在0.2米以下
* @param lon1 第一點的精度
* @param lat1 第一點的緯度
* @param lon2 第二點的精度
* @param lat3 第二點的緯度
* @return 返回的距離,單位km
* */
public static double GetDistance(double lon1,double lat1,double lon2, double lat2)
{
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double a = radLat1 - radLat2;
double b = rad(lon1) - rad(lon2);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2)+Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));
s = s * EARTH_RADIUS;
s = Math.round(s * 10000) / 10000;
return s;
}
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java工具類 六 根據經緯度計算距離