JavaScript 用ajax傳遞引數到後臺
阿新 • • 發佈：2019-01-05
用ajax傳遞引數時，會經常出現後臺接受不到引數的情況，解決如下
前端：
<script type="text/javascript"> var validateNum; function validateButton() { if (validateNum!=null){ if (document.getElementById("validateNum").value==validateNum){ var c=document.getElementById('submit'); c.type='submit'; }else { alert("不對"); } } } function success(text) { validateNum=text; } function fail(code) { var input = document.getElementById('test-response-text'); alert(code); } function startRequst1(){ var request = new XMLHttpRequest(); // 新建XMLHttpRequest物件 request.onreadystatechange = function () { // 狀態發生變化時，函式被回撥 if (request.readyState === 4) { // 成功完成 // 判斷響應結果: if (request.status === 200) { // 成功，通過responseText拿到響應的文字: alert(request.responseText); return success(request.responseText); } else { // 失敗，根據響應碼判斷失敗原因: return fail(request.status); } } else { // HTTP請求還在繼續... } }; // 傳送請求: var phoneNumber=document.getElementById("phoneNumber").value; request.open('POST', '/blog/sendValidateMsg',true); request.setRequestHeader("Content-type", "application/json; charset=utf-8"); request.send(phoneNumber);//傳遞單個引數 } </script> <body> <div class="body-mid-form"> <form action="/blog/register1" method="post"> <input type="text" placeholder="請輸入手機號碼" id="phoneNumber" name="phoneNumber"/> <br/> <input type="text" placeholder="請出入驗證碼" id="validateNum"/> <input type="button" value="點選獲取驗證碼" onclick="startRequst1();"/> <br/> <input type="text" placeholder="請輸入密碼" id="password" name="password"/> <br/> <input type="button" value="註冊" id="submit" onclick="validateButton()"/> </form> </div> </body> </html>
後臺獲取ajax傳遞來的引數：
@ResponseBody @RequestMapping("/blog/sendValidateMsg") public String sendValidateMsg(HttpServletRequest req){ //ajax傳遞過來的引數 的讀取 StringBuilder sb = new StringBuilder(); try { BufferedReader reader = req.getReader(); char[]buff = new char[1024]; int len; while((len = reader.read(buff)) != -1) { sb.append(buff,0, len); } } catch (IOException e) { e.printStackTrace(); } return sb.toString();//這便是傳遞過來的值 }
當用ajax傳遞多個值時：
request.send(JSON.stringify({ "phoneNumber": "1123546", "name": "Lucy" }));後臺接收：
StringBuilder sb = new StringBuilder(); try { BufferedReader reader = req.getReader(); char[]buff = new char[1024]; int len; while((len = reader.read(buff)) != -1) { sb.append(buff,0, len); } } catch (IOException e) { e.printStackTrace(); } String str=sb.toString(); JSONObject jsonObject=new JSONObject(str); String phoneNumber=jsonObject.getString("phoneNumber"); String name=jsonObject.getString("name"); //含有特殊字元的文字需要先進行轉碼 URLDecoder.decode(jsonObject.getString("text"), "UTF-8"));