1. 程式人生 > >資料庫設計(表與表之間的3種關係)

資料庫設計(表與表之間的3種關係)

表與表之間一般存在三種關係,即一對一,一對多,多對多關係。
下面分別就三種關係講解資料庫相關設計的思路和思考過程;

(1)一對一關係
例如,下面的一張表,儲存了人的相關資訊,有男有女,要求查處所有的夫妻。
sql程式碼:

CREATE TABLE IF NOT EXISTS person(
    id INT PRIMARY KEY AUTO_INCREMENT,
    sname VARCHAR(10),
    sex CHAR(1),
    husband INT,
    wife INT 
);
INSERT INTO person VALUES(1,'小花','0'
,3,0);
INSERT INTO person VALUES(2,'小明','1',0,4); INSERT INTO person VALUES(3,'張三','1',0,1); INSERT INTO person VALUES(4,'小麗','0',2,0); INSERT INTO person VALUES(5,'王五','1',0,0);

sql程式碼對應的person表:
這裡寫圖片描述
從表中可以看出,小花和張三是夫妻,小明和小麗是夫妻。通常為了查詢方便,需要兩個表,但實際專案中為了省空間,通常只建一個表,要實現一對一查詢,可以建立兩個檢視(虛表)
* 有個小細節提一下,檢視只是個邏輯概念,並不獨立佔用實體記憶體,它依附於資料表,對檢視進行修改時相應的表資料也會蓋改動*

CREATE VIEW men AS (SELECT * FROM person WHERE sex='1');
CREATE VIEW women AS (SELECT * FROM person WHERE sex='0');

men檢視:
這裡寫圖片描述
women檢視:
這裡寫圖片描述

執行查詢:
方式一(原始方法):SELECT men.sname AS husband,women.sname AS wife FROM men,women WHERE men.id = women.husband AND women.id = men.wife;

方式二(連線方法):SELECT men.sname AS husband,women.sname AS wife FROM men INNER JOIN women ON men.id = women.husband AND women.id = men.wife;

二、一對多關係
例如:一個人可以擁有多輛汽車,要求查詢某個人擁有的所有車輛。
分析:這種情況其實也可以採用 一張表,但因為一個人可以擁有多輛汽車,如果採用一張表,會造成冗餘資訊過多。好的設計方式是,人和車輛分別單獨建表,那麼如何將兩個表關聯呢?有個巧妙的方法,在車輛的表中加個外來鍵欄位(人的編號)即可。
* (思路小結:’建兩個表,一’方不動,’多’方新增一個外來鍵欄位)*

sql程式碼:

    //建立人員表
CREATE TABLE human(
    id VARCHAR(12) PRIMARY KEY,
    sname VARCHAR(12),
    age INT,
    sex CHAR(1)
);
INSERT INTO human VALUES('H001','小王',27,'1');
INSERT INTO human VALUES('H002','小明',24,'1');
INSERT INTO human VALUES('H003','張慧',28,'0');
INSERT INTO human VALUES('H004','李小燕',35,'0');
INSERT INTO human VALUES('H005','王大拿',29,'1');
INSERT INTO human VALUES('H006','周強',36,'1');
    //建立車輛資訊表
CREATE TABLE car(
    id VARCHAR(12) PRIMARY KEY,
    mark VARCHAR(24),
    price NUMERIC(6,2),
    hid VARCHAR(12),
    CONSTRAINT fk_human FOREIGN KEY(hid) REFERENCES human(id)
);
INSERT INTO car VALUES('C001','BMW',65.99,'H001');
INSERT INTO car VALUES('C002','BenZ',75.99,'H002');
INSERT INTO car VALUES('C003','Skoda',23.99,'H001');
INSERT INTO car VALUES('C004','Peugeot',20.99,'H003');
INSERT INTO car VALUES('C005','Porsche',295.99,'H004');
INSERT INTO car VALUES('C006','Honda',24.99,'H005');
INSERT INTO car VALUES('C007','Toyota',27.99,'H006');
INSERT INTO car VALUES('C008','Kia',18.99,'H002');
INSERT INTO car VALUES('C009','Bentley',309.99,'H005');

sql程式碼對應的人員表:
這裡寫圖片描述
sql程式碼對應的車輛資訊表:
這裡寫圖片描述
執行查詢:SELECT human.sname AS 車主,car.mark AS 車輛 FROM human,car WHERE human.id = car.hid;

`SELECT human.sname AS 車主,car.mark AS 車輛 FROM human INNER JOIN car WHERE human.id = car.hid;

三、多對多關係`
例如:學生選課,一個學生可以選修多門課程,每門課程可供多個學生選擇。
分析:這種方式可以按照類似一對多方式建表,但冗餘資訊太多,好的方式是實體和關係分離並單獨建表,實體表為學生表和課程表,關係表為選修表,其中關係表採用聯合主鍵的方式(由學生表主鍵和課程表主鍵組成)建表。

sql程式碼:

    //建立學生表
CREATE TABLE student(
    id VARCHAR(10) PRIMARY KEY,
    sname VARCHAR(12),
    age INT,
    sex CHAR(1),
    class VARCHAR(6)
);
INSERT INTO student VALUES('p0001','王軍',20,1,'c101');
INSERT INTO student VALUES('p0002','張宇',21,1,'c101');
INSERT INTO student VALUES('p0003','劉飛',22,1,'c102');
INSERT INTO student VALUES('p0004','趙燕',18,0,'c103');
INSERT INTO student VALUES('p0005','曾婷',19,0,'c103');
INSERT INTO student VALUES('p0006','周慧',21,0,'c104');
INSERT INTO student VALUES('p0007','小紅',23,0,'c104');
INSERT INTO student VALUES('p0008','楊曉',18,0,'c104');
INSERT INTO student VALUES('p0009','李傑',20,1,'c105');
INSERT INTO student VALUES('p0010','張良',22,1,'c105');

    //建立課程表
CREATE TABLE course(
    id VARCHAR(10) PRIMARY KEY,
    sname VARCHAR(12),
    credit NUMERIC(2,1),
    teacher VARCHAR(12)
);
INSERT INTO course VALUES('C001','Java',3.5,'李老師');
INSERT INTO course VALUES('C002','高等數學',5.0,'趙老師');
INSERT INTO course VALUES('C003','JavaScript',3.5,'王老師');
INSERT INTO course VALUES('C004','離散數學',3.5,'卜老師');
INSERT INTO course VALUES('C005','資料庫',3.5,'廖老師');
INSERT INTO course VALUES('C006','作業系統',3.5,'張老師');

    //建立選修表
CREATE TABLE sc(
    sid VARCHAR(10),
    cid VARCHAR(10)
);

ALTER TABLE sc ADD CONSTRAINT pk_sc PRIMARY KEY(sid,cid);
ALTER TABLE sc ADD CONSTRAINT fk_student FOREIGN KEY(sid) REFERENCES student(id);
ALTER TABLE sc ADD CONSTRAINT fk_course FOREIGN KEY(cid) REFERENCES course(id);

INSERT INTO sc VALUES('S0001','C001');
INSERT INTO sc VALUES('S0001','C002');
INSERT INTO sc VALUES('S0001','C003');
INSERT INTO sc VALUES('S0002','C001');
INSERT INTO sc VALUES('S0002','C004');
INSERT INTO sc VALUES('S0003','C002');
INSERT INTO sc VALUES('S0003','C005');
INSERT INTO sc VALUES('S0004','C003');
INSERT INTO sc VALUES('S0005','C001');
INSERT INTO sc VALUES('S0006','C004');
INSERT INTO sc VALUES('S0007','C002');
INSERT INTO sc VALUES('S0008','C003');
INSERT INTO sc VALUES('S0009','C001');
INSERT INTO sc VALUES('S0009','C005');

sql程式碼對應的學生表:
這裡寫圖片描述
sql程式碼對應的課程表:
這裡寫圖片描述
sql程式碼對應的選課表:
這裡寫圖片描述
執行查詢:(沒有選課的學生資訊和無學生選的課程資訊)
普通方式:

SELECT * FROM student WHERE student.id NOT IN (SELECT sid FROM sc);
SELECT * FROM course WHERE course.id NOT IN (SELECT cid FROM sc);

關聯方式:

SELECT student.* FROM student LEFT JOIN sc ON student.id=sc.sid LEFT JOIN course ON course.id = sc.cid WHERE course.sname IS NULL;
SELECT course.* FROM course LEFT JOIN sc ON course.id=sc.cid LEFT JOIN student ON student.id = sc.sid WHERE student.sname IS NULL;