文章目錄

• Springboot 讀取專案下的Json檔案成物件
• 1、建立Json檔案
• 2、建立讀取工具類
• 3、讀取
• 4、輸出

Springboot 讀取專案下的Json檔案成物件

1、建立Json檔案

{
  "age": 30,
  "comment": "哈哈哈",
  "name": "小明",
  "sex": 1
}

2、建立讀取工具類

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.parser.Feature;
import org.springframework.core.io.ClassPathResource;

import java.io.IOException;
import java.lang.reflect.Type;
import java.nio.charset.StandardCharsets;

/**
 * @author Created by 譚健 on 2019/1/7. 星期一. 13:07.
 * © All Rights Reserved.
 */
public class JsonUtils {


    public static <T> T readJsonFromClassPath(String path, Type type) throws IOException {

        ClassPathResource resource = new ClassPathResource(path);
        if (resource.exists()) {
            return JSON.parseObject(resource.getInputStream(), StandardCharsets.UTF_8, type,
                    // 自動關閉流
                    Feature.AutoCloseSource,
                    // 允許註釋
                    Feature.AllowComment,
                    // 允許單引號
                    Feature.AllowSingleQuotes,
                    // 使用 Big decimal
                    Feature.UseBigDecimal);
        } else {
            throw new IOException();
        }
    }
}

 

3、讀取

		// 讀取專案路徑下的檔案 json/person.json
        Person person = JsonUtils.readJsonFromClassPath("json/person.json", Person.class);
        System.out.println(person.toString());

4、輸出

ReadJson.Person(name=小明, age=30, sex=1, comment=哈哈哈)