C# 判斷字串是否為2進位制,8進位制,10進位制,16進位制
阿新 • • 發佈：2019-01-08
原始碼只能判斷只要含有符合條件的字元就返回true,現修改為每個字元都要符合/// <summary> /// 判斷是否十六進位制格式字串 /// </summary> /// <param name="str">字串</param> /// <returns>true 是 false 不是</returns> public static bool IsHexadecimal(string str) { if (str == "") return false; const string PATTERN = @"[A-Fa-f0-9]+$"; bool sign = false; for (int i = 0; i < str.Length; i++) { sign=System.Text.RegularExpressions.Regex.IsMatch(str[i].ToString(), PATTERN); if (!sign) { return sign; } } return sign; } /// <summary> /// 判斷是否八進位制格式字串 /// </summary> /// <param name="str">字串</param> /// <returns>true 是 false 不是</returns> public static bool IsOctal(string str) { if (str == "") return false; const string PATTERN = @"[0-7]+$"; bool sign = false; for (int i = 0; i < str.Length; i++) { sign = System.Text.RegularExpressions.Regex.IsMatch(str[i].ToString(), PATTERN); if (!sign) { return sign; } } return sign; } /// <summary> /// 判斷是否二進位制格式字串 /// </summary> /// <param name="str">字串</param> /// <returns>true 是 false 不是</returns> public static bool IsBinary(string str) { if (str == "") return false; const string PATTERN = @"[0-1]+$"; bool sign = false; for (int i = 0; i < str.Length; i++) { sign = System.Text.RegularExpressions.Regex.IsMatch(str[i].ToString(), PATTERN); if (!sign) { return sign; } } return sign; } /// <summary> /// 判斷是否十進位制格式字串 /// </summary> /// <param name="str">字串</param> /// <returns>true 是 false 不是</returns> public static bool IsDecimal(string str) { if (str == "") return false; const string PATTERN = @"[0-9]+$"; bool sign = false; for (int i = 0; i < str.Length; i++) { sign = System.Text.RegularExpressions.Regex.IsMatch(str[i].ToString(), PATTERN); if (!sign) { return sign; } } return sign; }