[LeetCode]24. Swap Nodes in Pairs兩兩交換連結串列中的節點
阿新 • • 發佈:2019-01-13
Given a linked list, swap every two adjacent nodes and return its head.
Example:
Given1->2->3->4
, you should return the list as2->1->4->3
.
Note:
- Your algorithm should use only constant extra space.
- You may not modify the values in the list's nodes, only nodes itself may be changed.
要求把相鄰的2個節點兩兩互換,還必須是換指標而不能是隻換值
這裡我們用遞迴的方法來處理,兩個指標l1和l2,l1-->l2,我們先把l1和l2換了,然後對l1.next.next繼續相同的方法遞迴下去
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution {public ListNode swapPairs(ListNode head) { if (head==null || head.next==null) return head; ListNode res = head.next; head.next = swapPairs(head.next.next); res.next = head; return res; } }