leetcode-1-two sum

阿新 • • 發佈：2019-01-21

一個很好的leetcode題解部落格：點選開啟連結

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0 
] + nums[1] = 2 + 7 = 9,
return [0, 1].

思路：遍歷每個數得到target-數之後的結果看有沒有對應，如果有的話返回其索引。所以想到建立數與下標之間的索引。空間換時間。

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        unordered_map<int, int> m; //建立索引表
        for(int i=0;i<nums.size();i++){
            m[nums[i]]=i;
        }
        vector<int > ret(2);
        for(int i=0;i<nums.size();i++){
            int now = target-nums[i];
            if(m[now]){
                ret[0]=i;
                ret[1]=m[now];
                break;
            }
        }
        return ret;
    }
};

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leetcode-1-two sum

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