轉載：http://zhidao.baidu.com/link?url=IqxAQMkf0qRbYNqKKmjLLZ_zSZOQf-RGJ5lmokc04VDLDQJWS1MP14lFnevGB2rCS0WtifXaAAcqRmEqNY8tHq

我有兩張表：Teacher id(主鍵) name 
            Student id(主鍵) name tid(外來鍵對應Teacher的id)

public List findStudentByTeacher(Teacher teacher) {
  try {
   session = this.openSession();
   String HQL = "select s.name from Student as s where s.tid
 
 ="+teacher.getId();
   query = session.createQuery(HQL);
   return query.list();
  } catch (Exception e) {
   e.printStackTrace();
   logs.error("查詢學生時候出現錯誤！");
   return null;
  }finally{
   this.closeSession(session);
  }
 }
呼叫時出現異常：
org.hibernate.QueryException: could not resolve property: tid of: com.accp.hibernate.po.Student [select s.name from com.accp.hibernate.po.Student as s where s.tid =2]
 at org.hibernate.persister.entity.AbstractPropertyMapping.throwPropertyException(AbstractPropertyMapping.java:43)
 at 
...
...
2008-11-04 16:57:10,203 [com.accp.hibernate.dao.BusinessDAOimpt]-[ERROR] 查詢學生時候出現錯誤！
我tid為2的學生有很多 為什麼？？
請問要配置什麼？還是HQL語句寫的有問題？

能改嗎？
在那裡能改？
是
 <many-to-one name="teacher" class="com.accp.hibernate.po.Teacher" fetch="select">
            <column name="tid" not-null="true" />
        </many-to-one>

改為：String HQL = "select s.name from Student as s where s.teacher.id ="+teacher.getId();