從百度copy來一個備份的指令碼，做了簡單的修改：

#!/bin/bash  

# Backup file is saved in the directory, if it does not exist Create  
basepath='/database/3306/backup/'  
   
if [ ! -d "$basepath" ]; then  
  mkdir -p "$basepath"  
fi  
   
mysqldump -uroot -p''  -S /tmp/mysql_3306.sock xuning --tables  auto  >$basepath/sit3_ccbak_$(date +%F).sql
   
# Delete the backup data to 7 days before  
find $basepath -mtime +7 -name "*.sql" -exec rm -rf {} \; 


find /database/3306/backup/ -mtime +7  -name "*.sql" -exec rm -rf {} \;
 

-----------------------------------------------------------------------------------------------直接執行這個指令碼報錯：[roo[email protected] backup]# sh sit3_cc.sh: command not found : command not found : command not found : command not found 'it3_cc.sh: line 9: syntax error near unexpected token `'it3_cc.sh: line 9: `fi 後發現執行腳本里面mysqldump命令需要自己輸入密碼。百度查下指令碼下執行mysqldump指令碼化的使用方法 ，需要自己的家目錄下建立一個隱藏檔案[

[email protected] backup]# vim /root/.my.cnf[[email protected] backup]# cat /root/.my.cnf [mysqldump]user=rootpassword=這樣在命令中不要指定密碼-p欄位之後的指令碼還是會報錯。報錯是find：bin/sh^M: bad interpreter: No such file or directory後來發現還是因為編碼的格式不對導致的可以:set ff 檢視編碼--findfind /database/3306/backup/ -mtime +7 -name "*.sql" -exec rm -rf {} \;-exec<執行指令>：假設find指令的回傳值為True，就執行該指令；-mtime<24小時數>：查詢在指定時間曾被更改過的檔案或目錄，單位以24小時計算；之後寫定時任務crontab -e22 22 * * * sh /database/che/backup/sit3_ccbak.sh