蛇形填數

描述

在n*n方陳裡填入1,2,...,n*n,要求填成蛇形。例如n=4時方陳為：
10 11 12 1
9 16 13 2
8 15 14 3
7 6 5 4

輸入

直接輸入方陳的維數，即n的值。(n<=100)

輸出

輸出結果是蛇形方陳。

樣例輸入

3

樣例輸出

7 8 1
6 9 2
5 4 3

程式碼

import java.util.Scanner;

public class Test33 {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int[][] a=new int[100][100];  
        int i,j,k=1;  
        for (i=0;i<n/2;i++)  
        {  
            for (j=i;j<=n-2-i;j++)   
                a[j][n-i-1]=k++;  
            for (j=n-1-i;j>=i+1;j--)   
                a[n-1-i][j]=k++;  
            for (j=n-i-1;j>=i+1;j--)  
                a[j][i]=k++;  
            for (j=i;j<=n-2-i;j++)   
                a[i][j]=k++;  
        }  
        if (n%2==1)      
        {  
            i=n/2;  
            a[i][i]=n*n;  
        }  
        for (i=0;i<n;i++)   
        {  
            for (j=0;j<n;j++)  
                System.out.print(a[i][j]+" ");  
            System.out.print("\n");  
        }  
        sc.close();
	}

}
 

另一種解法

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		int sum = 0;
		int x,y;
		int[][] a = new int[N][N];
		sum = a[x=0][y=N-1] = 1;
		while (sum < N*N)
		{
			while(x+1<N && a[x+1][y]==0) 
				a[++x][y] = ++sum;
			while(y-1>=0 && a[x][y-1]==0)
				a[x][--y] = ++sum;
			while(x-1>=0 && a[x-1][y]==0)
				a[--x][y] = ++sum;
			while(y+1<N && a[x][y+1]==0) 
				a[x][++y] = ++sum;
		}
		for (int i = 0; i < N; i++) {
			for (int j = 0; j < N; j++)
				System.out.print(a[i][j]+" ");
			System.out.print("\n");
		}
	}
		
}