Fragment中載入網頁(WebView)監聽Back鍵 ,實現返回上一頁的功能
阿新 • • 發佈:2019-01-28
首先建立一個抽象類BackHandledFragment,該類有一個抽象方法onBackPressed(),所有BackHandledFragment的子類在onBackPressed方法中處理各自對Back事件的消費邏輯。onBackPressed返回布林值,宿主Activity將會根據該方法的返回值判斷子Fragment是否有消費Back事件。此外,宿主FragmentActivity還會保持一份當前Fragment的引用,當用戶按下Back鍵時,宿主Activity會判斷當前Fragment是否需要消費該事件,如果沒有Fragment消費才會自己消費。
宿主FragmentActivity需要實現BackHandledIntegerface,子Fragment會通過該介面告訴宿主FragmentActivity自己是當前螢幕可見的Fragment。public abstract class BackHandledFragment extends Fragment{ protected BackHandledInterface mBackHandledInterface; /** * 所有繼承BackHandledFragment的子類都將在這個方法中實現物理Back鍵按下後的邏輯 * FragmentActivity捕捉到物理返回鍵點選事件後會首先詢問Fragment是否消費該事件 * 如果沒有Fragment訊息時FragmentActivity自己才會消費該事件 */ public abstract boolean onBackPressed(); @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); if(!(getActivity() instanceof BackHandledInterface)){ throw new ClassCastException("Hosting Activity must implement BackHandledInterface"); }else{ this.mBackHandledInterface = (BackHandledInterface)getActivity(); } } @Override public void onStart() { super.onStart(); //告訴FragmentActivity,當前Fragment在棧頂 mBackHandledInterface.setSelectedFragment(this); } }
public interface BackHandledInterface {
void setSelectedFragment(BackHandledFragment selectedFragment);
}
所以在Fragment的onCreate中會判斷宿主FragmentActivity是否已繼承了該介面。在Fragment的onStart()方法中就會呼叫該介面告訴宿主FragmentActivity自己是當前螢幕可見的Fragment。
宿主FragmentActivity就可以在onBackPressed()方法中對Back事件進行判斷處理了。
public class MainActivity extends FragmentActivity implements BackHandledInterface{ private BackHandledFragment mBackHandedFragment; private boolean hadIntercept; @Override public void setSelectedFragment(BackHandledFragment selectedFragment) { this.mBackHandedFragment = selectedFragment; } @Override public void onBackPressed() { if(mBackHandedFragment == null || !mBackHandedFragment.onBackPressed()){ if(getSupportFragmentManager().getBackStackEntryCount() == 0){ super.onBackPressed(); //退出 }else{ getSupportFragmentManager().popBackStack(); //fragment 出棧 } } } }
Fragment需要繼承抽象類BackHandledFragment,並覆寫抽象方法onBackPressed(),在抽象方法中判斷WebView是否可以返回到之前開啟的網頁
public class WorkFragment extends BackHandledFragment {
private WebView webView;
private WebSettings webSettings;
private String url = "https://www.baidu.com/";
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.work_fragment,container,false);
webView = (WebView)view.findViewById(R.id.workWebView);
webSettings = webView.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setUseWideViewPort(true);
webSettings.setLoadWithOverviewMode(true);
webView.setWebViewClient(new MyWebViewClient());
webView.loadUrl(url);
return view;
}
private class MyWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// return super.shouldOverrideUrlLoading(view, url);
view.loadUrl(url);
return true;
}
@Override
public void onReceivedError(WebView view, int errorCode,
String description, String failingUrl) {
// super.onReceivedError(view, errorCode, description, failingUrl);
// Toast.makeText(this,"網頁載入錯誤!",0).show();
}
}
@Override
public boolean onBackPressed(){
if(webView.canGoBack()){
webView.goBack();
Log.v("webView.goBack()", "webView.goBack()");
return true;
}else{
Log.v("Conversatio退出","Conversatio退出");
return false;
}
}
}
參考:http://blog.csdn.net/guxiao1201/article/details/40507387