從C++轉java，在使用函數傳對象時，碰到一點問題，今天特意驗證了一下：

public class App 
{
    public static void doubleTest(double d) {
        d=8.0;
        System.out.println( "[INNER doubleTest]double:"+d);
    }
    public static void DoubleTest(Double dd) {
        dd=8.0;
        System.out.println( "[INNER DoubleTest]Double:"+dd);
    }
    
 
public static void ObjectTest(ObjectChange obj) {
        obj = new ObjectChange(5);
        System.out.println( "[INNER ObjectTest]Object:"+obj.getTT());
        obj.setTT(8);
        System.out.println( "[INNER ObjectTest]Object:"+obj.getTT());
    }
    public static void ObjectChangeTest(ObjectChange obj) {
        obj.setTT(
 
8);
        System.out.println( "[INNER ObjectChangeTest]Object:"+obj.getTT());
        obj = new ObjectChange(5);
        System.out.println( "[INNER ObjectChangeTest]Object:"+obj.getTT());
        obj.setTT(6);
        System.out.println( "[INNER ObjectChangeTest]Object:"+obj.getTT());
    }
    
    
 
public static void main( String[] args )
    {
        System.out.println( "Source:" );
        double d1=1;
        Double d2=2.0;
        ObjectChange obj1 = new ObjectChange(1);
        System.out.println( "double:"+d1+"    Double:"+d2 +"    Object:"+ obj1.getTT());        

        System.out.println( "After:" );
        doubleTest(d1);
        DoubleTest(d2);
        ObjectTest(obj1);
        System.out.println( "double:"+d1+"    Double:"+d2 +"    Object:"+ obj1.getTT());
        ObjectChangeTest(obj1);
        System.out.println( "Object:"+ obj1.getTT());
    }
}

程序輸出結果：

總結：

obj在函數體內作為臨時變量，可讀取對象內容，采用“=”（賦值運算符）改變的是臨時對象的內容，賦值後，再操作的也是臨時對象的內容；

只有在賦值前調用對象的成員方法（setTT()）才能真正改變obj對象的內容；

java中函數傳值與引用問題