1. 程式人生 > >poj1094貼一份TLE的程式碼,以後有可能再優化。

poj1094貼一份TLE的程式碼,以後有可能再優化。

//poj1094 寫了兩個DFS,TLE 話說我輸入一次它就來兩個DFS,能不TLE嗎?
//我看Discuss有測試資料,跑了一下,真的很慢,腦殘的孩子果然只有慢慢學。
//貼一份TLE的程式碼,備份一下,說不定哪天我可以繼續優化,然後AC。
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;
int top = 0;
bool isSource[31];
bool isCircle;
bool isComplete;
int list[31][31];
int child[31];
bool mark[31]; 
int stack[1000000];
bool tempMark[31];
bool allMark(int n)
{
	for (int i = 0; i < n; i++)
	{
		if (!mark[i])
			return false;
	}
	return true;
}
bool dfs()
{
	for (int i = 0; i < child[stack[top - 1]]; i++)
	{
		if (mark[list[stack[top - 1]][i]])
			return true;
		else
		{
			mark[list[stack[top - 1]][i]] = true;
			tempMark[list[stack[top - 1]][i]];
			stack[top++] = list[stack[top - 1]][i];
			if (dfs())
				return true;
		}
	}
	mark[stack[top - 1]] = false;
	top--;
	if (top == 0)
		return false;
	return false;
}
bool dfs2(int n)
{
	if (allMark(n))
		return true;
	for (int i = 0; i < child[stack[top - 1]]; i++)
	{
		if (!mark[list[stack[top - 1]][i]])
		{
			mark[list[stack[top - 1]][i]] = true;
			tempMark[list[stack[top - 1]][i]] = true;
			stack[top++] = list[stack[top - 1]][i];
			if (dfs2(n))
				return true;
		}
	}
	mark[stack[top - 1]] = false;
	top--;
	if (top == 0)
		return false;
	return false;
}
void checkIsCircle(int n)
{
	memset(tempMark, 0, sizeof(tempMark));
	for (int i = 0; i < n; i++)
	{
		if (tempMark[i])
			continue;
		top = 0;
		memset(mark, 0, sizeof(mark));
		stack[top++] = i;
		mark[i] = true;
		tempMark[i] = true;
		if (dfs())
		{
			isCircle = true;
			return;
		}
	}
}
void checkIsComplete(int n)
{
	memset(tempMark, 0, sizeof(tempMark));
	for (int i = 0; i < n; i++)
	{
		if (isSource[i] && !tempMark[i])
		{
			top = 0;
			memset(mark, 0, sizeof(mark));
			stack[top++] = i;
			mark[i] = true;
			tempMark[i] = true;
			if (dfs2(n))
			{
				isComplete = true;
				return;
			}
		}
	}
}
int main()
{
	int n, m;
	cin >> n >> m;
	while (n && m)
	{
		isCircle = false;
		isComplete = false;
		bool ok = false;
		for (int i = 0; i < n; i++)
		{
			isSource[i] = true;
			mark[i] = false;
			child[i] = 0;
			for (int j = 0; j < n; j++)
				list[i][j] = 0;
		}
		for (int i = 0; i < m; i++)
		{
			char s, c, t;
			cin >> s >> c >> t;
			int st = s - 'A';
			int ed = t - 'A';
			if (c == '<')
			{
				list[st][child[st]++] = ed;
				isSource[ed] = false;
			}
			else
			{
				list[ed][child[ed]++] = st;
				isSource[st] = false;
			}
			//對於是有向圖的起點的,採用遍歷看是否有環,然後看是否完整。
			checkIsCircle(n);
			if (isCircle && !ok)
			{
				cout << "Inconsistency found after " << i + 1 << " relations." << endl;
				ok = true;
			}
			else
			{
				checkIsComplete(n);
				if (isComplete && !ok)
				{
					cout << "Sorted sequence determined after " << i + 1 << " relations: ";
					for (int i = 0; i < top; i++)
						cout << char('A' + stack[i]);
					cout << "." << endl;
					ok = true;
				}
			}
			
		}
		if (!isCircle && !isComplete)
			cout << "Sorted sequence cannot be determined." << endl;
		cin >> n >> m;
	}
	return 0;
}