1. 程式人生 > >Python學習筆記(6) -- 字元轉數字、字串轉整型(char2num、str2int)

Python學習筆記(6) -- 字元轉數字、字串轉整型(char2num、str2int)

原文連結:

http://www.liaoxuefeng.com/wiki/0014316089557264a6b348958f449949df42a6d3a2e542c000/0014317852443934a86aa5bb5ea47fbbd5f35282b331335000

但是如果要把序列[1, 3, 5, 7, 9]變換成整數13579reduce就可以派上用場:

>>> from functools import reduce
>>> def fn(x, y):
...     return x * 10 + y
...
>>> reduce(fn, [1
, 3, 5, 7, 9]) 13579

這個例子本身沒多大用處,但是,如果考慮到字串str也是一個序列,對上面的例子稍加改動,配合map(),我們就可以寫出把str轉換為int的函式:

>>> from functools import reduce
>>> def fn(x, y):
...     return x * 10 + y
...
>>> def char2num(s):
...     return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7
, '8': 8, '9': 9}[s] ... >>> reduce(fn, map(char2num, '13579')) 13579

整理成一個str2int的函式就是:

from functools import reduce

def str2int(s):
    def fn(x, y):
        return x * 10 + y
    def char2num(s):
        return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9
}[s] return reduce(fn, map(char2num, s))

還可以用lambda函式進一步簡化成:

from functools import reduce

def char2num(s):
    return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s]

def str2int(s):
    return reduce(lambda x, y: x * 10 + y, map(char2num, s))