SQL Server中以星期一為每週第一天 計算週數
阿新 • • 發佈:2019-02-01
SQLServer中以星期一為每週第一天 計算週數,但是在網上搜了,看了一些,比如如下的文章:
寫的都挺複雜,一堆的sql程式碼,但是實際運行了一下,都是不對的。。。
比如下面是摘自網上的程式碼:
經過驗證,發現寫的是有問題的。。。DECLARE @DATE DATETIME = '2012-01-29' DECLARE @FIRST_DATE_OF_YEAR DATETIME = DATEADD(YYYY, DATEDIFF(YYYY, 0, @DATE), 0) SELECT DATEPART(WEEK, @DATE) , -- 一年中的週數,預設以週日開始 DATEADD(WK, DATEDIFF(WK, 0, @DATE), 0) , -- 當前周的週一,預設從週日開始,但是仍然找週一 DATEADD(DAY, -1, DATEADD(WK, DATEDIFF(WK, 0, @DATE), 0)) , -- 當前周先找週一,然後往前一天找到週日 DATEDIFF(DAYOFYEAR, @FIRST_DATE_OF_YEAR, DATEADD(DAY, -1, DATEADD(WK, DATEDIFF(WK, 0, @DATE), 0))) , -- 當前天離年第一天的間隔 DATEDIFF(DAYOFYEAR, @FIRST_DATE_OF_YEAR, DATEADD(DAY, -1, DATEADD(WK, DATEDIFF(WK, 0, @DATE), 0))) / 7 + 1 -- 按天計算的週數
由於急著要用,就想怎麼用簡單的方法,就能算出來呢?
下面這個是簡單的方法:
SELECT GETDATE() AS THEDAY,
case when datepart(weekday,getdate()) in (2,3,4,5,6,7) then DATEPART(WEEK,GETDATE())
else DATEPART(WEEK,GETDATE()) -1
end AS WEEKS
/*
THEDAY WEEKS
2017-03-15 10:55:12.193 11
*/
考慮到週日可能是一年的第一天,所以改成這樣:
select getdate() as today, case when datepart(weekday,getdate()) in (2,3,4,5,6,7) and DATEPART(WEEKday,datename(year,getdate())+'-01-01') = 1 then datepart(week,getdate()) +1 when datepart(weekday,getdate()) =1 and DATEPART(WEEKday,datename(year,getdate())+'-01-01') = 1 then datepart(week,getdate()) when datepart(weekday,getdate()) in (2,3,4,5,6,7) then datepart(week,getdate()) else datepart(week,getdate()) -1 end as week /* today week 2017-03-15 10:55:53.507 */