- (void)viewDidLoad {
    [super viewDidLoad];
    self.title = @"Button點選效果測試";

    self.tableView.delaysContentTouches = NO;

    // iOS7
    for (id view in self.tableView.subviews)
    {
        if ([NSStringFromClass([view class]) isEqualToString:@"UITableViewWrapperView"])
        {
            if
 
([view isKindOfClass:[UIScrollView class]])
            {
                UIScrollView *scroll = (UIScrollView *) view;
                scroll.delaysContentTouches = NO;
            }
            break;
        }
    }

    // iOS8 注意，本人測試系統iOS10，沒有走這個方法，走上面那個方法
    for (id view in self.tableView.subviews
 
)
    {
        if ([NSStringFromClass([view class]) isEqualToString:@"UITableViewCellScrollView"])
        {
            if([view isKindOfClass:[UIScrollView class]])
            {
                UIScrollView *scroll = (UIScrollView *) view;
                scroll.delaysContentTouches = NO;
            }
            break
 
;
        }
    }

    // 該方式相當於上面兩個迴圈的合集，並且實現方式更加優雅，推薦使用它，而不是使用上面兩個迴圈
    for (id obj in self.tableView.subviews) {
        if ([obj respondsToSelector:@selector(setDelaysContentTouches:)]) {
            [obj setDelaysContentTouches:NO];
        }
    }
}

解決方案二：

-(void)touchesBegan:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event{
    [super touchesBegan:touches withEvent:event];
    [NSOperationQueue.mainQueue addOperationWithBlock:^{ self.highlighted = YES;}];
}

-(void)touchesCancelled:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event{
    [super touchesCancelled:touches withEvent:event];
    [self performSelector:@selector(setDefault) withObject:nil afterDelay:0.1];
}

-(void)touchesEnded:(NSSet<UITouch *> *)touches withEvent:(UIEvent *)event{
    [super touchesEnded:touches withEvent:event];
    [self performSelector:@selector(setDefault) withObject:nil afterDelay:0.1];
}

- (void)setDefault
{
    [NSOperationQueue.mainQueue addOperationWithBlock:^{ self.highlighted = NO; }];
}

該方案比較簡單粗暴，我們建立一個UIButton的分類，然後將它匯入pch檔案中，就徹底解決了button的點選效果問題，比起方案一要簡單一些